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    <blockquote> <p>What would I need to do from here to back up the file pointer so it writes to the same line I'm reading from?</p> </blockquote> <p>This doesn't help, unless every line you intend to write is the same length as the line you're replacing (in which case the tools you're looking for are <a href="http://perldoc.perl.org/functions/seek.html" rel="nofollow noreferrer">seek</a> and <a href="http://perldoc.perl.org/functions/tell.html" rel="nofollow noreferrer">tell</a>). For ordinary editing though, the standard file model just doesn't cut it for replacing bits in-place.</p> <p>Fortunately, Perl comes with a feature that makes what you need easy, called "in-place editing mode", in which the source file is either renamed or unlinked, and the output directed to a new file with the same name. Most often it's used by enabling the <code>-i</code> <a href="http://perldoc.perl.org/perlrun.html#Command-Switches" rel="nofollow noreferrer">command-line switch</a> together with the <code>-p</code> or <code>-n</code> switches for line-wise editing, but you can also enable it within a program using the <code>$^I</code> <a href="http://perldoc.perl.org/perlvar.html" rel="nofollow noreferrer">special variable</a>.</p> <p>Example code:</p> <pre><code>{ # Create a scope to localize variables in. # If you want to back up the originals, set $^I to ".bak" instead. local $^I = ""; # Set @ARGV to the file you want to process, or a list of files. local @ARGV = ("file.txt"); while (my $line = &lt;&gt;) { # Process $line here. print $line; } } </code></pre>
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    1. POHow do I read a file line by line while modifying lines as needed?
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    1. COJust gave this a try and it worked beautifully! Thank you!
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      1. USFrancis Lewis
 

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