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PODataGrid: dynamic DataTemplate for dynamic DataGridTemplateColumn
 

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    <p>I want to show data in a datagrid where the data is a collection of</p> <pre><code>public class Thing { public string Foo { get; set; } public string Bar { get; set; } public List&lt;Candidate&gt; Candidates { get; set; } } public class Candidate { public string FirstName { get; set; } public string LastName { get; set; } ... } </code></pre> <p>where the number of candidates in Candidates list varies at runtime.</p> <p>Desired grid layout looks like this</p> <pre><code>Foo | Bar | Candidate 1 | Candidate 2 | ... | Candidate N </code></pre> <p>I'd like to have a <code>DataTemplate</code> for each <em>Candidate</em> as I plan changing it during runtime - user can choose what info about candidate is displayed in different columns (candidate is just an example, I have different object). That means I also want to change the column templates in runtime although this can be achieved by one big template and collapsing its parts.</p> <p>I know about two ways how to achieve my goals (both quite similar):</p> <ol> <li>Use <code>AutoGeneratingColumn</code> event and create <em>Candidates</em> columns</li> <li>Add Columns manually</li> </ol> <p>In both cases I need to load the <code>DataTemplate</code> from string with <code>XamlReader</code>. Before that I have to edit the string to change the binding to wanted <em>Candidate</em>.</p> <p><strong>Is there a better way how to create a DataGrid with unknown number of DataGridTemplateColumn?</strong></p> <p><em>Note:</em> This question is based on <a href="https://stackoverflow.com/questions/652304/dynamic-datatemplate-with-valueconverter">dynamic datatemplate with valueconverter</a></p> <p><strong>Edit:</strong> As I need to support both WPF and Silverlight, I've created my own <code>DataGrid</code> component which has <code>DependencyProperty</code> for bindig a collection of columns. When the collection changes, I update the columns.</p>
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    1. USLukas Cenovsky
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    1. CODid you ever get a resolution or answer for this problem?
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      1. USKirk Broadhurst
    2. CONot really. As I wrote I've ended up with custom `DataGrid` control. But I'm thinking of developing a custom control based on just a `Grid` as `DataGrid` is quite heavy for my task.
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      1. USLukas Cenovsky
 

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