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    <p>The keyword <code>super</code> doesn't "stick". Every method call is handled individually, so even if you got to <code>SuperClass.method1()</code> by calling <code>super</code>, that doesn't influence any other method call that you might make in the future.</p> <p>That means there is no direct way to call <code>SuperClass.method2()</code> from <code>SuperClass.method1()</code> without going though <code>SubClass.method2()</code> unless you're working with an actual instance of <code>SuperClass</code>.</p> <p>You can't even achieve the desired effect using Reflection (see <a href="http://download.oracle.com/javase/6/docs/api/java/lang/reflect/Method.html#invoke%28java.lang.Object%2C%20java.lang.Object...%29" rel="noreferrer">the documentation of <code>java.lang.reflect.Method.invoke(Object, Object...)</code></a>).</p> <p><strong>[EDIT]</strong> There still seems to be some confusion. Let me try a different explanation.</p> <p>When you invoke <code>foo()</code>, you actually invoke <code>this.foo()</code>. Java simply lets you omit the <code>this</code>. In the example in the question, the type of <code>this</code> is <code>SubClass</code>.</p> <p>So when Java executes the code in <code>SuperClass.method1()</code>, it eventually arrives at <code>this.method2();</code></p> <p>Using <code>super</code> doesn't change the instance pointed to by <code>this</code>. So the call goes to <code>SubClass.method2()</code> since <code>this</code> is of type <code>SubClass</code>.</p> <p>Maybe it's easier to understand when you imagine that Java passes <code>this</code> as a hidden first parameter:</p> <pre><code>public class SuperClass { public void method1(SuperClass this) { System.out.println("superclass method1"); this.method2(this); // &lt;--- this == mSubClass } public void method2(SuperClass this) { System.out.println("superclass method2"); } } public class SubClass extends SuperClass { @Override public void method1(SubClass this) { System.out.println("subclass method1"); super.method1(this); } @Override public void method2(SubClass this) { System.out.println("subclass method2"); } } public class Demo { public static void main(String[] args) { SubClass mSubClass = new SubClass(); mSubClass.method1(mSubClass); } } </code></pre> <p>If you follow the call stack, you can see that <code>this</code> never changes, it's always the instance created in <code>main()</code>.</p>
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