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    <p>The problem is that you aren't actually passing in image data for the <code>image1</code> and <code>image2</code> arguments. You're just passing character strings containing the image file names <code>'keyframe1.jpg'</code> and <code>'keyframe2.jpg'</code>.</p> <p>You need to load the image data from the files first using <a href="http://www.mathworks.com/help/techdoc/ref/imread.html" rel="nofollow">IMREAD</a>, then pass the image data to <code>im_reg_MI</code>. Assuming the images are in the current working directory, you would do something like this:</p> <pre><code>image1 = imread('keyframe1.jpg'); image2 = imread('keyframe2.jpg'); [h,im_matched,theta,I,J] = im_reg_MI(image1,image2,0,1); </code></pre> <p><strong>EDIT:</strong></p> <p>There seems to be an additional error within <code>im_reg_MI</code> that occurs if <code>image21</code> (the rotated version of <code>image2</code>) is the same size or smaller than <code>image1</code> for one or more of its dimensions. If <code>m1</code> were less than or equal to <code>m</code> and/or <code>n1</code> were less than or equal to <code>n</code>, then one or both of the loops for <code>i</code> or <code>j</code> would never be entered since <code>1:step:(m1-m)</code> and/or <code>1:step:(n1-n)</code> would <a href="http://www.mathworks.com/help/techdoc/ref/colon.html" rel="nofollow">create an empty vector</a>. Thus, the inner loop code would never be run and <code>h</code> would never be created.</p> <p><strong>And one extra note...</strong></p> <p>I noticed that the function <code>im_reg_MI</code> appears to treat the two images as 2-D, which means they must be <a href="http://www.mathworks.com/help/techdoc/creating_plots/f2-10709.html#f2-175" rel="nofollow">intensity images</a> (i.e. grayscale or binary image data). If you're dealing with <a href="http://www.mathworks.com/help/techdoc/creating_plots/f2-10709.html#f2-155" rel="nofollow">indexed</a> or <a href="http://www.mathworks.com/help/techdoc/creating_plots/f2-10709.html#f2-12468" rel="nofollow">RGB</a> image data, I don't think <code>im_reg_MI</code> is going to handle them properly.</p>
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    1. COHi gnovice. Thanks for the help. I followed your suggestion and pass the image data to im_reg_MI, but the same error came out again. Btw, for you information, the MI2(im1,im2) which is called in the above code is under the same directory. I guess it shouldn't be the problem. I don't know which part is wrong.
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    2. CO@appi: I found an additional potential error within `im_reg_MI` that occurs for certain image sizes. I added an explanation of it to my answer.
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    3. COThanks for the explanation! It helps me a lot!
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