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    <p>If you're looking to do this at compile time (which is the only way to perform initializers similar to what you have in your question), you can let the initializer define the size f your array:</p> <pre><code>char string[] = {34,34,34,21,45,12,45,12, 0}; // added a 0 to the end to // make it '\0' terminated // You might not need that </code></pre> <p>If you want your string to take it's data from a runtime source (a file or other input), you'll need to perform the allocation yourself, and exactly how to do it depends on how you're going to be getting the data. </p> <p>The following example reads data from <code>stdin</code> into a dynamically allocated character array, growing the array as needed until EOF is reached. It grows the array by 20 bytes each time so you can easily check what's happening in a debugger, but a real life program would do better to grow by something larger like by doubling the size or just growing in increments of 100KB - the details of your expected data should guide you in this decision).</p> <pre><code>#include &lt;stdlib.h&gt; #include &lt;stdio.h&gt; void fatal_error(void); int main( int argc, char** argv) { int buf_size = 0; int buf_used = 0; char* buf = NULL; char* tmp = NULL; char c; int i = 0; while ((c = getchar()) != EOF) { if (buf_used == buf_size) { //need more space in the array buf_size += 20; tmp = realloc(buf, buf_size); // get a new larger array if (!tmp) fatal_error(); buf = tmp; } buf[buf_used] = c; // pointer can be indexed like an array ++buf_used; } puts("\n\n*** Dump of stdin ***\n"); for (i = 0; i &lt; buf_used; ++i) { putchar(buf[i]); } free(buf); return 0; } void fatal_error(void) { fputs("fatal error - out of memory\n", stderr); exit(1); } </code></pre>
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    1. USMichael Burr
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