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    <p><strong>Edit</strong></p> <p>Better than before approach without using helper vectors: (<a href="http://www.ideone.com/wRHYv" rel="nofollow">source on ideone</a>):</p> <pre><code>#include &lt;vector&gt; #include &lt;algorithm&gt; #include &lt;iostream&gt; template&lt;class Vals&gt; void sortingPermutation(const Vals&amp; values, std::vector&lt;int&gt;&amp; v){ int size = values.size(); v.clear(); v.reserve(size); for(int i=0; i &lt; size; ++i) v.push_back(i); std::sort(v.begin(), v.end(), [&amp;values](int a, int b) -&gt; bool { return values[a] &lt; values[b]; }); } int main() { std::vector&lt;double&gt; values; values.push_back(24); values.push_back(55); values.push_back(22); values.push_back(1); std::vector&lt;int&gt; permutation; sortingPermutation(values, permutation); typedef std::vector&lt;int&gt;::const_iterator I; for (I p = permutation.begin(); p != permutation.end(); ++p) std::cout &lt;&lt; *p &lt;&lt; " "; std::cout &lt;&lt; "\n"; } </code></pre> <p>I am using lambda from C++0x, but it can be replaced with simple functor object:</p> <pre><code>template&lt;class T&gt; struct CmpPairs{ CmpPairs(const std::vector&lt;T&gt; &amp;v): v_(v) {} std::vector&lt;T&gt; v_; bool operator()(int a, int b){ return v_[a] &lt; v_[b]; } }; template&lt;class T&gt; CmpPairs&lt;T&gt; CreateCmpPairs(const std::vector&lt;T&gt; &amp; v) { return CmpPairs&lt;T&gt;(v); } //in sortingPermutation: std::sort(v.begin(), v.end(), CreateCmpPairs(values)); </code></pre> <p>Source of old solution with <code>std::map</code>: <a href="http://www.ideone.com/k1Fxj" rel="nofollow">ideone</a></p>
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    1. USPawel Zubrycki
    1. USPawel Zubrycki
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    1. COThe rule-of-thumb I've seen is that sorting a vector is more efficient than using a self-sorting container. Never tested it to see how true it is.
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      1. USMark Ransom
    2. COEven better one with use of C++0x (lambda could be replaced with functor): http://www.ideone.com/wRHYv I think much better than antonakos'es, because there are no helper objects just to sort.
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      1. USPawel Zubrycki
 

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