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    <p>No, there's no difference between <code>"</code> and <code>'</code> for quoting strings other than that you can use <code>"</code> without escaping it inside a string quoted with <code>'</code> and vice-versa. But I don't think that (the title of your question) actually has anything to do with the problem you're having.</p> <p>Re your edit, if you want to ensure that there are no characters with the value 0 or 255 in the string, you can do that like this:</p> <pre><code>data = data.replace(/[\u0000\u00ff]/g, ''); </code></pre> <p>...before passing it to <code>eval</code>. And it sounds like you might want to do that, since your thing is saying it's received 37 bytes but the string is only 36 characters long and doesn't use any characters requiring two bytes (or perhaps it just has a space at the end I can't see).</p> <p><strong>Off-topic</strong>: It's best not to use <code>eval</code> to deserialize JSON. Instead, use a library that handles it directly. Crockford has two different non-<code>eval</code> libs on <a href="https://github.com/douglascrockford/JSON-js" rel="nofollow">his github page</a>, one (json_parse.js) that uses a recursive-descent parser and another (json_parse_state.js) that uses a state machine. If you really, really want to use <code>eval</code> to parse JSON, take a look at his implementation in json2.js, which at least takes a couple of steps to weed out malicious stuff.</p> <p><strong>Off-topic 2</strong>: Re</p> <blockquote> <p>where <code>data = { "cmd": "setname", "params": "ok" }</code> (with quotes i suppose, because of typeof(data) being = string).</p> </blockquote> <p>We only use quotes to quote string literals in code; there are no quotes around actual string data itself in memory. If I do this:</p> <pre><code>var foo = "bar"; </code></pre> <p>...the string that <code>foo</code> points to consists entirely of the characters b, a, and r. There are no quotes; the quotes are only there in the code to tell the parser that what follows is a string literal.</p>
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    1. COactually i'm not using eval(). i'm using json2.js with JSON.parse() but both give me the same result... i'll try your data.replace() thank you.EDIT » i did d = d.replace(/[\u0000-\u00ff]/g, ''); but now d is empty (0 length) but still typeof(d) = string
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    2. CO@mwm: I'm afraid you saw an interim version where I'd typed `-` where I shouldn't have. The correct regex is (now) shown above (just delete the `-`). :-) V. embarrassing, I kind of hoped I'd caught it before anyone saw it, but apparently not.
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    3. COwell i should learn some regex too. thank you. that actually worked! which means that i was right, supposing some web-sockets implementation chars were conflicting. i thought the browser unwraped the string correctly. thank you very much @T.J. Crowder
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