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POInit a shared_ptr of reference ( std::tr1::shared_ptr<class&> )
 

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    <p>I'm using a library which returns a reference to me.<br> I need to use this reference as class-attribute.<br> Not being able to initialize the attribute in constructor directly (the lib needs to be inited before), I thought about using a shared_ptr for lazy initialization:</p> <pre><code>#include &lt;iostream&gt; #include &lt;string&gt; #include &lt;tr1/memory&gt; //This is library, cannot touch std::string globalString = "TEST"; std::string&amp; getStringReference() { return globalString; } //this is my class which uses the library class Foo { public: Foo() : testString_( std::tr1::shared_ptr&lt; std::string&amp; &gt;() ) { //do some initialization of the library here... //now init the shared_ptr testString_.reset( getStringReference() ); } std::string getString() const { return *testString_; } private: std::tr1::shared_ptr&lt; std::string&amp; &gt; testString_; }; //and a main to be compilable and check if the above works... int main() { Foo foo; std::cout &lt;&lt; foo.getString() &lt;&lt; std::endl; } </code></pre> <p>But unfortunately this does not work. g++ gives messages like this:</p> <pre><code>error: forming pointer to reference type ‘std::string&amp;’ </code></pre> <p>I tried some other ways to get the reference into the shared_ptr, but nothing works... Perhaps you could give me a hint.</p> <p>Note:<br> - In "real-world" instead of std::string the datatype is a class without default constructor.<br> - For those who still wonder: The above is just a simplified example-code :)</p> <p><strong>UPDATE:</strong><br> - While trying to apply the suggestions, I found out that contrary to the used std::string from example, my class has a private copy constructor. This means I'm not able to just copy the object into a new one.</p>
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    1. COThe answers helped me to find the right way, but I couldn't mark more than one as accepted. I chose the one which finally let me get the point, but the others aren't false therefore.
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