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    <p>PHP with GD can't do such a thing in an acceptable way, processing an image pixel-by-pixel will be really slow...</p> <p>Imagick does support a function that enable you to write your own expression (<a href="http://www.php.net/manual/en/function.imagick-fximage.php" rel="nofollow">fximage</a>), after that everything will be handled internally within Imagick.</p> <p>So I've find a way to do what you've requested in Imagick, I've taked the expression from <a href="http://scottpenberthy.com/2008/09/05/fisheye-effect-in-imagemagick/" rel="nofollow">"Scott builds Software" blog - fisheye effect in imagick</a>. You can read the full explanation of the expression in his blog. Further documentation of this function is available at the official <a href="http://www.imagemagick.org/script/fx.php" rel="nofollow">ImageMagick</a> site, you can learn there how you can build your own expressions.</p> <p>Please note that the PHP documentation about the return value is incorrect, I've also commented there. The function return the actual Imagick object.</p> <p>So here is your code:</p> <pre><code>&lt;?php /* Create new object */ $im = new Imagick(); /* Create new checkerboard pattern */ $im-&gt;newPseudoImage(100, 100, "pattern:checkerboard"); /* Set the image format to png */ $im-&gt;setImageFormat('png'); /* Fill background area with transparent */ $trans = Imagick::VIRTUALPIXELMETHOD_TRANSPARENT; $im-&gt;setImageVirtualPixelMethod($trans); /* Activate matte */ $im-&gt;setImageMatte(true); /* This is the expression that define how to do the fisheye effect */ $distort_expression = 'kk=w*0.5; ll=h*0.5; dx=(i-kk); dy=(j-ll); aa=atan2(dy,dx); rr=hypot(dy,dx); rs=rr*rr/hypot(kk,ll); px=kk+rs*cos(aa); py=ll+rs*sin(aa); p{px,py}'; /* Perform the distortion */ $im = $im-&gt;fxImage($distort_expression); /* Ouput the image */ header("Content-Type: image/png"); echo $im; ?&gt; </code></pre> <p>Anyway, keep in mind that this is still slow, be careful with whatever you do with that...</p>
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    1. POHow to create a fisheye effect with PHP GD
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    1. COThank you very much! You are my hero! :D
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