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    <p>A string is a list of <em>characters</em> (i.e. code points). The number of bytes taken to represent the string <strong>depends entirely on which encoding you use to turn it into bytes</strong>.</p> <p>That said, you can turn the string into a byte array and then look at its size as follows:</p> <pre><code>// The input string for this test final String string = "Hello World"; // Check length, in characters System.out.println(string.length()); // prints "11" // Check encoded sizes final byte[] utf8Bytes = string.getBytes("UTF-8"); System.out.println(utf8Bytes.length); // prints "11" final byte[] utf16Bytes= string.getBytes("UTF-16"); System.out.println(utf16Bytes.length); // prints "24" final byte[] utf32Bytes = string.getBytes("UTF-32"); System.out.println(utf32Bytes.length); // prints "44" final byte[] isoBytes = string.getBytes("ISO-8859-1"); System.out.println(isoBytes.length); // prints "11" final byte[] winBytes = string.getBytes("CP1252"); System.out.println(winBytes.length); // prints "11" </code></pre> <p>So you see, even a simple "ASCII" string can have different number of bytes in its representation, depending which encoding is used. Use whichever character set you're interested in for your case, as the argument to <code>getBytes()</code>. And don't fall into the trap of assuming that UTF-8 represents <em>every</em> character as a single byte, as that's not true either:</p> <pre><code>final String interesting = "\uF93D\uF936\uF949\uF942"; // Chinese ideograms // Check length, in characters System.out.println(interesting.length()); // prints "4" // Check encoded sizes final byte[] utf8Bytes = interesting.getBytes("UTF-8"); System.out.println(utf8Bytes.length); // prints "12" final byte[] utf16Bytes= interesting.getBytes("UTF-16"); System.out.println(utf16Bytes.length); // prints "10" final byte[] utf32Bytes = interesting.getBytes("UTF-32"); System.out.println(utf32Bytes.length); // prints "16" final byte[] isoBytes = interesting.getBytes("ISO-8859-1"); System.out.println(isoBytes.length); // prints "4" (probably encoded "????") final byte[] winBytes = interesting.getBytes("CP1252"); System.out.println(winBytes.length); // prints "4" (probably encoded "????") </code></pre> <p>(Note that if you don't provide a character set argument, the platform's <em>default character set</em> is used. This might be useful in some contexts, but in general you should avoid depending on defaults, and always use an explicit character set when encoding/decoding is required.)</p>
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    1. PObytes of a string in java?
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    1. USAndrzej Doyle
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    1. COso again if i use getBytes().it will give me the length same as x.length am i wrong because i am not sure
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    2. CO@Green Ash The length of the byte array -- getBytes() -- and x.length MAY be equal but is not guaranteed to be so. It will be equal if all the characters are represented by a single byte each. This will always hold true for character encodings that use a single byte per character (or less), such as ISO-8859-1. UTF-8 uses either 1 or 2 bytes, so it depends on the exact characters in the string. Then there are character encodings that always use two bytes per character.
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    3. COi like your answer :) , so they might in somehow be the same but not always am i right? o.k. then is it ok to use the method without the parameter because it causing to me an error!!
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