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    <p>There is no difference when written on its own (as shown) - in both cases myInt will be incremented by 1.</p> <p>But there is a difference when you use it in an expression, e.g. something like this:</p> <pre><code>MyFunction(++myInt); MyFunction(myInt++); </code></pre> <p>In the first case, myInt is incremented and the new/incremented value is passed to MyFunction(). In the second case, the old value of myInt is passed to MyFunction() (but myInt is still incremented before the function is called).</p> <p>Another example is this:</p> <pre><code>int myInt = 1; int a = ++myInt; // myInt is incremented by one and then assigned to a. // Both myInt and a are now 2. int b = myInt++; // myInt is assigned to b and then incremented by one. // b is now 2, myInt is now 3 </code></pre> <p>BTW: as <a href="https://stackoverflow.com/users/52682/don-music">Don</a> pointed out in a comment the same rules are also valid for decrement operations, and the correct terminology for these operations are:</p> <pre><code>++i; // pre-increment i++; // post-increment --i; // pre-decrement i--; // post-decrement </code></pre> <p>As <a href="https://stackoverflow.com/users/22656/jon-skeet">Jon Skeet</a> points out:</p> <blockquote> <p>Others have shown where it makes a difference, and have commented that as a single statement it doesn't make a difference.</p> <p>I'd like to add that it's almost always a bad idea to use it where it makes a difference. I suspect there may be some times where it's more readable to have code such as:</p> <pre><code>Console.WriteLine("Foo: {0}", foo++); </code></pre> <p>than:</p> <pre><code>Console.WriteLine("Foo: {0}", foo); foo++; </code></pre> <p>... but they're very rare! The latter of these two samples makes the ordering crystal clear immediately - the former requires a bit of thinking (to my poor brain, anyway). Think of the readability first.</p> </blockquote>
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    1. POIn C# what is the difference between myInt++ and ++myInt?
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    1. POIn C# what is the difference between myInt++ and ++myInt?
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    1. CO++myInt is usually one instruction faster but this can obviously be optimized by the compiler
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      1. USJoe Phillips
    2. COare you sure it's incremented after the function is called? i remember having read a thread where they say it's incremented before the call, but the old value is given to the function as argument. it makes diff when myInt is also visible within the function. this would also be the case in c++.
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      1. USJohannes Schaub - litb
    3. CO@litb: you are right, I will update the answer. Thanks a lot.
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