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    <p>As it was correctly pointed out by @Gabe, you left some white-spaces unhandled:</p> <pre><code>scala&gt; object SchemeParsers extends RegexParsers { | | private def space = regex("[ \\n]*".r) | | // Scheme boolean #t and #f translate to Scala's true and false | private def bool : Parser[Boolean] = | ("#t" | "#f") ^^ {case "#t" =&gt; true; case "#f" =&gt; false} | | // A Scheme identifier allows alphanumeric chars, some symbols, and | // can't start with a digit | private def id : Parser[String] = | """[a-zA-Z=*+/&lt;&gt;!\?][a-zA-Z0-9=*+/&lt;&gt;!\?]*""".r | | // This interpreter only accepts numbers as integers | private def num : Parser[Int] = """-?\d+""".r ^^ {case s =&gt; s toInt} | | // A string can have any character except ", and is wrapped in " | private def str : Parser[String] = '"' ~&gt; """[^""]*""".r &lt;~ '"' &lt;~ space ^^ {case s =&gt; s} | | // A Scheme list is a series of expressions wrapped in () | private def list : Parser[List[Any]] = | '(' ~&gt; space ~&gt; rep(expr) &lt;~ ')' &lt;~ space ^^ {s: List[Any] =&gt; s} | | // A Scheme expression contains any of the other constructions | private def expr : Parser[Any] = id | str | num | bool | list ^^ {case s =&gt; s} | | def parseExpr(str: String) = parse(expr, str) | } defined module SchemeParsers scala&gt; SchemeParsers.parseExpr("""(("a" "b") ("a" "b"))""") res12: SchemeParsers.ParseResult[Any] = [1.22] parsed: List(List(a, b), List(a, b)) scala&gt; SchemeParsers.parseExpr("""("a" "b" "c")""") res13: SchemeParsers.ParseResult[Any] = [1.14] parsed: List(a, b, c) scala&gt; SchemeParsers.parseExpr("""((1) (1 2) (1 2 3))""") res14: SchemeParsers.ParseResult[Any] = [1.20] parsed: List(List(1), List(1, 2), List(1, 2, 3)) </code></pre>
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    1. POParsing Scheme using Scala parser combinators
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    1. USVasil Remeniuk
    1. USVasil Remeniuk
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    1. COExcellent! Thank you! I thought the Regex parser handled whitespace for me, but I see I was mistaken.
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      1. USstomcavage
    2. CO`RegexParsers` skip space automatically at the beginning of any literal string or regular expression. I wonder if the problem is related to the `Char` being used...
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      1. USDaniel C. Sobral
    3. CO@stomcavage `RegexParsers` does handle space for you, just not with `Char`.
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      1. USDaniel C. Sobral
 

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