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    <p>here is a simple tree example using SQL Server 2005:</p> <pre><code>--go through a nested table supervisor - user table and display the chain DECLARE @Contacts table (id varchar(6), first_name varchar(10), reports_to_id varchar(6)) INSERT @Contacts VALUES ('1','Jerome', NULL ) -- tree is as follows: INSERT @Contacts VALUES ('2','Joe' ,'1') -- 1-Jerome INSERT @Contacts VALUES ('3','Paul' ,'2') -- / \ INSERT @Contacts VALUES ('4','Jack' ,'3') -- 2-Joe 9-Bill INSERT @Contacts VALUES ('5','Daniel','3') -- / \ \ INSERT @Contacts VALUES ('6','David' ,'2') -- 3-Paul 6-David 10-Sam INSERT @Contacts VALUES ('7','Ian' ,'6') -- / \ / \ INSERT @Contacts VALUES ('8','Helen' ,'6') -- 4-Jack 5-Daniel 7-Ian 8-Helen INSERT @Contacts VALUES ('9','Bill ' ,'1') -- INSERT @Contacts VALUES ('10','Sam' ,'9') -- DECLARE @Root_id char(4) --get 2 and below SET @Root_id=2 PRINT '@Root_id='+COALESCE(''''+@Root_id+'''','null') ;WITH StaffTree AS ( SELECT c.id, c.first_name, c.reports_to_id, c.reports_to_id as Manager_id, cc.first_name AS Manager_first_name, 1 AS LevelOf FROM @Contacts c LEFT OUTER JOIN @Contacts cc ON c.reports_to_id=cc.id WHERE c.id=@Root_id OR (@Root_id IS NULL AND c.reports_to_id IS NULL) UNION ALL SELECT s.id, s.first_name, s.reports_to_id, t.id, t.first_name, t.LevelOf+1 FROM StaffTree t INNER JOIN @Contacts s ON t.id=s.reports_to_id WHERE s.reports_to_id=@Root_id OR @Root_id IS NULL OR t.LevelOf&gt;1 ) SELECT * FROM StaffTree </code></pre> <p>output:</p> <pre><code>@Root_id='2 ' id first_name reports_to_id Manager_id Manager_first_name LevelOf ------ ---------- ------------- ---------- ------------------ ----------- 2 Joe 1 1 Jerome 1 3 Paul 2 2 Joe 2 6 David 2 2 Joe 2 7 Ian 6 6 David 3 8 Helen 6 6 David 3 4 Jack 3 3 Paul 3 5 Daniel 3 3 Paul 3 (7 row(s) affected) </code></pre> <p>change @Root_id to get different output:</p> <pre><code>@Root_id=null id first_name reports_to_id Manager_id Manager_first_name LevelOf ------ ---------- ------------- ---------- ------------------ ----------- 1 Jerome NULL NULL NULL 1 2 Joe 1 1 Jerome 2 9 Bill 1 1 Jerome 2 10 Sam 9 9 Bill 3 3 Paul 2 2 Joe 3 6 David 2 2 Joe 3 7 Ian 6 6 David 4 8 Helen 6 6 David 4 4 Jack 3 3 Paul 4 5 Daniel 3 3 Paul 4 (10 row(s) affected) </code></pre>
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    1. PORepresent a product taxonomy in database
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    1. CONot a very good example of design though. No keys or RI and all the columns are nullable.
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    2. CO@dportas, I did say `simple tree example`. This provides a much better basic understanding of the issue than only suggesting to "google" search of the topic (like you do in your answer: http://stackoverflow.com/questions/4335971/represent-a-product-taxonomy-in-database/4336114#4336114).
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