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POSFTP in Python? (platform independent)
 

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    <p>I'm working on a simple tool that transfers files to a hard-coded location with the password also hard-coded. I'm a python novice, but thanks to ftplib, it was easy:</p> <pre><code>import ftplib info= ('someuser', 'password') #hard-coded def putfile(file, site, dir, user=(), verbose=True): """ upload a file by ftp to a site/directory login hard-coded, binary transfer """ if verbose: print 'Uploading', file local = open(file, 'rb') remote = ftplib.FTP(site) remote.login(*user) remote.cwd(dir) remote.storbinary('STOR ' + file, local, 1024) remote.quit() local.close() if verbose: print 'Upload done.' if __name__ == '__main__': site = 'somewhere.com' #hard-coded dir = './uploads/' #hard-coded import sys, getpass putfile(sys.argv[1], site, dir, user=info) </code></pre> <p>The problem is that I can't find any library that supports sFTP. What's the normal way to do something like this securely? </p> <p>Edit: Thanks to the answers here, I've gotten it working with Paramiko and this was the syntax.</p> <pre><code>import paramiko host = "THEHOST.com" #hard-coded port = 22 transport = paramiko.Transport((host, port)) password = "THEPASSWORD" #hard-coded username = "THEUSERNAME" #hard-coded transport.connect(username = username, password = password) sftp = paramiko.SFTPClient.from_transport(transport) import sys path = './THETARGETDIRECTORY/' + sys.argv[1] #hard-coded localpath = sys.argv[1] sftp.put(localpath, path) sftp.close() transport.close() print 'Upload done.' </code></pre> <p>Thanks again!</p>
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    1. USMark Wilbur
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    1. COThanks ! Got an SFTP upload script working in 5 minutes :)
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      1. USOhad Schneider
 

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