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    <p>If you have access to the accelerometer, you can use the <a href="http://bit.ly/fjJ0dk" rel="nofollow" title="getOrientation()">getOrientation()</a> method, which returns azimuth, pitch, and roll as determined from the two sensors, and calculated via the <a href="http://bit.ly/hU1jxV" rel="nofollow" title="getRotationMatrix()">getRotationMatrix()</a> method.</p> <p><strong>EDITS</strong></p> <p>Response to comments... I see your question now. Sorry. With just the 3-axis magnetometer, you can't accurately get azimuth, pitch, and roll except when the device is parallel to the surface of the earth. Remember using a needle compass and having it either a) on a spindle so you can see and manually compensate for tilt, or b) sealed in liquid so you can get the bubble level to the center? To get azimuth: </p> <pre><code>azimuth = arctan(y/x) </code></pre> <p>Now, if you tilt the phone, the errors in the x/y plane sensing can get big. Now you need to figure out the tilt (with the accelerometer), then measure the Z-axis magnetic strength, and then use the three to compensate. This is essentially what you know as getRotationMatrix() and getOrientation().</p> <p>Part of the reason I think Sensor.TYPE_ORIENTATION was deprecated in API 8 was because there isn't a separate orientation sensor <strong>per se</strong>. It is a combination of magnetic field and acceleration sensing.</p> <p>A good paper that I dug up that covers it all:</p> <p><a href="http://www.ssec.honeywell.com/position-sensors/datasheets/sae.pdf" rel="nofollow">http://www.ssec.honeywell.com/position-sensors/datasheets/sae.pdf</a></p>
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    1. POgetting info from magnetic sensors
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    1. COUnderstood. My question is more along the lines of "how do you do anything useful with values for ambient magnetic field in the X, Y and Z axis?"
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    2. COYou don't!! Instead of re-inventing the wheel, simply use the orientation sensor & rotation-matrix.
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