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    <p>Here is what I would recommend. Create a div that contains the dynamic content and put that content in a partial view. In this case there would be a partial view called Products.ascx</p> <pre><code> &lt;div id="ProductsContent"&gt; &lt;% Html.RenderPartial("Products"); %&gt; &lt;/div&gt; </code></pre> <p>Call a javascript function when a category checkbox is clicked.</p> <pre><code>&lt;input id="Category_1" type="checkbox" onclick="CategoryCheckChanged(1)" /&gt; &lt;input id="Category_2" type="checkbox" onclick="CategoryCheckChanged(2)" /&gt; &lt;input id="Category_3" type="checkbox" onclick="CategoryCheckChanged(3)" /&gt; </code></pre> <p>use JQuery to detect the value of the checkbox, then post to the server. In the example below my controller name is called Products. The information returned from the server is the updated partial view, which replaces the div contents.</p> <pre><code>function CheckChanged(id) { var bChecked = $("#Category_"+id).attr("checked"); var value = 0; if(bChecked) value=1; $.post('&lt;%= Url.Action("CategoryChanged","Products") %&gt;' , { value: value, categoryid: id } , function(data) { if (data.success) { alert("Sweet !") //update the div with the new content $('#ProductsContent').html(data.newcontent); } else { alert("Bummer:" + data.msg); } }, "json"); } </code></pre> <p>Here is the CategoryChanged function in ProductsController</p> <pre><code> [HttpPost] public ActionResult CategoryChanged(int value, int id) { try { //Save the change to the database SaveChangedCategoryValueToDatabase(id,value); //Create your View Model MyProductsViewModel vm = new MyProductsViewModel(); return Json(new { success = true, newcontent = MyViewHelper.RenderPartialToString(this.ControllerContext, "~/Views/Products/Products.ascx", new ViewDataDictionary(vm), new TempDataDictionary()) }); } catch(SystemException ex) { return Json(new { success = false, msg = ex.Message }); } } </code></pre> <p>and finally... The helper function that takes renders a partial view to a string.</p> <pre><code>public static class MyViewHelper { public static string RenderPartialToString(ControllerContext context , string partialViewName , ViewDataDictionary viewData , TempDataDictionary tempData) { ViewEngineResult result = ViewEngines.Engines.FindPartialView(context, partialViewName); if (result.View != null) { StringBuilder sb = new StringBuilder(); using (StringWriter sw = new StringWriter(sb)) { using (HtmlTextWriter output = new HtmlTextWriter(sw)) { ViewContext viewContext = new ViewContext( context, result.View, viewData, tempData, output); result.View.Render(viewContext, output); } } return sb.ToString(); } return String.Empty; } } </code></pre>
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    1. POASP.NET MVC - Populating a form dynamically through the database
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    1. USCraig Howard
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      1. VTUpMod
    1. CORenderParitalToString is rather slow (I used to use it). When we converted from MVC 1 to 2 we had to dump the renderpartialtostring approach. Ajax.BeginForm is much cleanerand automatically replaces or appends in the view returned by the action. Plus you can execute javascript after the new content is loaded in place for any post-processing.
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      1. USCaptain Cosmodrome
 

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Guidance
A row detail

Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

Related data can be related in a to-one or a to-many fashion. Captions of data related in a to-many fashion link to a list view showing a filtered view of the table.

Try moving around until you find a non-empty to-many entry and click on the label to get to one. You can move back to the root by clicking on the database name in the header.

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