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POpass an array from jQuery to PHP (and actually go to the page after submit)
 

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  1. POpass an array from jQuery to PHP (and actually go to the page after submit)
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    <p>This seems like it would have been simple, but what i was doing was creating an array in jQuery and sending it to a php via ajax and inserting the records into a db. But what i want to do now is create the array exactly the same but instead of ajax, i'd like to go to the php page and view what it has received.</p> <p>How would i go about doing this?</p> <p>I'm using this jQuery:</p> <pre><code>$('#preview').live('click',function(){ var postData = {}; $('#items tr').not(':first').each(function(index, value) { var keyPrefix = 'data[' + index + ']'; postData[keyPrefix + '[index]'] = index; postData[keyPrefix + '[supp_short_code]'] = $(this).closest('tr').find('.supp_short_code').text(); postData[keyPrefix + '[project_ref]'] = $(this).closest('tr').find('.project_ref').text(); postData[keyPrefix + '[om_part_no]'] = $(this).closest('tr').find('.om_part_no').text(); postData[keyPrefix + '[description]'] = $(this).closest('tr').find('.description').text(); postData[keyPrefix + '[quantity_input]'] = $(this).closest('tr').find('.quantity_input').val(); postData[keyPrefix + '[cost_of_items]'] = $(this).closest('tr').find('.cost_of_items').text(); postData[keyPrefix + '[cost_total_td]'] = $(this).closest('tr').find('.cost_total_td').text(); }); $.ajax ({ type: "POST", url: "preview.php", dataType: "json", data: postData, cache: false, success: function() { } }); }); </code></pre> <p>And this PHP:</p> <pre><code>if (isset($_POST['data']) &amp;&amp; is_array($_POST['data'])) { foreach ($_POST['data'] as $row =&gt; $data) { echo $data['index']; echo $data['project_ref']; echo $data['supp_short_code']; echo $data['om_part_no']; echo $data['description']; echo $data['quantity_input']; echo $data['cost_of_items']; echo $data['cost_total_td']; } } </code></pre>
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    1. COWhat is it that you get? Any error message? What is your problem?
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    2. COSorry, theres no error, but what i'm saying is that this is using ajax, what i want to do is like a hyperlink and actually go to the php page. Not just get an ajax response!
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