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POBest way to test for a variable's existence in PHP; isset() is clearly broken
 

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  1. POBest way to test for a variable's existence in PHP; isset() is clearly broken
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    <p>From the <a href="http://php.net/isset" rel="noreferrer"><code>isset()</code> docs</a>:</p> <pre><code>isset() will return FALSE if testing a variable that has been set to NULL. </code></pre> <p>Basically, <code>isset()</code> doesn't check for whether the variable is set at all, but whether it's set to anything but <code>NULL</code>.</p> <p>Given that, what's the best way to actually check for the existence of a variable? I tried something like:</p> <pre><code>if(isset($v) || @is_null($v)) </code></pre> <p>(the <code>@</code> is necessary to avoid the warning when <code>$v</code> is not set) but <code>is_null()</code> has a similar problem to <code>isset()</code>: it returns <code>TRUE</code> on unset variables! It also appears that:</p> <pre><code>@($v === NULL) </code></pre> <p>works exactly like <code>@is_null($v)</code>, so that's out, too.</p> <p>How are we supposed to reliably check for the existence of a variable in PHP?</p> <hr> <p>Edit: there is clearly a difference in PHP between variables that are not set, and variables that are set to <code>NULL</code>:</p> <pre><code>&lt;?php $a = array('b' =&gt; NULL); var_dump($a); </code></pre> <p>PHP shows that <code>$a['b']</code> exists, and has a <code>NULL</code> value. If you add:</p> <pre><code>var_dump(isset($a['b'])); var_dump(isset($a['c'])); </code></pre> <p>you can see the ambiguity I'm talking about with the <code>isset()</code> function. Here's the output of all three of these <code>var_dump()s</code>:</p> <pre><code>array(1) { ["b"]=&gt; NULL } bool(false) bool(false) </code></pre> <hr> <p>Further edit: two things.</p> <p>One, a use case. An array being turned into the data of an SQL <code>UPDATE</code> statement, where the array's keys are the table's columns, and the array's values are the values to be applied to each column. Any of the table's columns can hold a <code>NULL</code> value, signified by passing a <code>NULL</code> value in the array. You <em>need</em> a way to differentiate between an array key not existing, and an array's value being set to <code>NULL</code>; that's the difference between not updating the column's value and updating the column's value to <code>NULL</code>.</p> <p>Second, <a href="https://stackoverflow.com/questions/418066/best-way-to-test-for-a-variables-existence-in-php-isset-is-clearly-broken#418162">Zoredache's answer</a>, <code>array_key_exists()</code> works correctly, for my above use case and for any global variables:</p> <pre><code>&lt;?php $a = NULL; var_dump(array_key_exists('a', $GLOBALS)); var_dump(array_key_exists('b', $GLOBALS)); </code></pre> <p>outputs:</p> <pre><code>bool(true) bool(false) </code></pre> <p>Since that properly handles just about everywhere I can see there being any ambiguity between variables that don't exist and variables that are set to <code>NULL</code>, <strong>I'm calling <code>array_key_exists()</code> the official easiest way in PHP to truly check for the existence of a variable</strong>.</p> <p>(Only other case I can think of is for class properties, for which there's <code>property_exists()</code>, which, according to <a href="http://php.net/property_exists" rel="noreferrer">its docs</a>, works similarly to <code>array_key_exists()</code> in that it properly distinguishes between not being set and being set to <code>NULL</code>.)</p>
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    1. COYou can't check - but why do you need to?
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    2. COYes, a good example for why you really need this would be helpful.
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    3. COI agree. As far as you need to know, neither are set because they are both null. You can't use them for anything.
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