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POPython sqlite3: UPDATE failure claims "no such column"
 

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    <p>The following script evokes the following exception in the UPDATE command. What I think should happen for this simple UPDATE command is that the value of db_2.foo.bar should be doubled from 1 to 2. My guess is that I have some subtle syntax error in the UPDATE statement (or else a bug at the Python or sqlite3 level); however, I've pored over the sqlite3 documentation -- especially the "UPDATE" and "expression" pages -- and don't see that I'm doing anything wrong. </p> <pre><code>db_1.foo_bar= (1,) Traceback (most recent call last): File "try2.py", line 29, in &lt;module&gt; db_2.execute( 'UPDATE foo SET bar = bar + db_1.foo.bar WHERE rowid = db_1.foo.rowid' ) sqlite3.OperationalError: no such column: db_1.foo.bar </code></pre> <p>Any suggestions or workarounds?</p> <pre><code>import sqlite3 # Create db_1, populate it and close it: open( 'db_1.sqlite', 'w+' ) db_1 = sqlite3.connect( 'db_1.sqlite' ) db_1.execute( 'CREATE TABLE foo(bar INTEGER)' ) db_1.execute( 'INSERT INTO foo (bar) VALUES (1)' ) db_1.commit() db_1.close() # Create db_2: open( 'db_2.sqlite', 'w+' ) db_2 = sqlite3.connect( 'db_2.sqlite' ) db_2.execute( 'CREATE TABLE foo(bar INTEGER)' ) # Attach db_1 to db_2 connection: db_2.execute( 'ATTACH "db_1.sqlite" AS db_1' ) # Populate db_2 from db_1: db_2.execute( 'INSERT INTO foo SELECT ALL * FROM db_1.foo' ) # Show that db_1.foo.bar exists: cur_2 = db_2.cursor() cur_2.execute( 'SELECT bar from db_1.foo' ) for result in cur_2.fetchall(): print 'db_1.foo_bar=', result # However, the following claims that db_1.foo.bar does not exist: db_2.execute( 'UPDATE foo SET bar = bar + db_1.foo.bar WHERE rowid = db_1.foo.rowid' ) db_2.execute( 'DETACH db_1') db_2.commit() db_2.close() </code></pre>
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