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    <p>In Rails routing, a 'resource' refers to the standard 7 routes that are created for RESTful resources: <code>index</code>, <code>show</code>, <code>new</code>, <code>create</code>, <code>edit</code>, <code>update</code> and <code>destroy</code>. Normally that is enough, but sometimes you might want to create another action.</p> <p>In the model, you want to create a <code>scope</code> that only returns special users:</p> <pre><code>class User &lt; ActiveRecord::Base scope :special, where(:special =&gt; true) end </code></pre> <p>On the controller side, there are two ways to go about this. What you are suggesting is the creation of an additional action:</p> <pre><code>match "/users/special" =&gt; "users#special" resource :users </code></pre> <p>In the controller, your special action would return the scope you just created:</p> <pre><code>class UsersController &lt; ApplicationController def special @users = User.special end end </code></pre> <p>That will do what you ask, but I would suggest NOT doing it this way. What if you add other flags later that you want to search by? What if you want to search by multiple flags? This solution isn't flexible enough for that. Instead, keep the routes the way they are:</p> <pre><code>resource :users </code></pre> <p>and just add an additional line to your controller:</p> <pre><code>class UsersController &lt; ApplicationController def index @users = User.all @users = @users.special if params[:special] end end </code></pre> <p>and now, when you want to display special users, simply direct the user to <code>/users?special=true</code></p> <p>This approach is much more future-proof, IMO.</p> <p>(This answer is assuming Rails-3. If you're still using 2.3 let me know)</p>
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    1. POHow do I create a resource that is the sub-set of an existing resource
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    1. USAdam Lassek
    1. USAdam Lassek
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    1. POHow do I create a resource that is the sub-set of an existing resource
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    1. COThere's no need for the lambda in your first example. This will do: scope: special, where(special: true)
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      1. USnoodl
    2. CO@noodl Thanks, still getting accustomed to arel.
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      1. USAdam Lassek
    3. COThanks! Beautiful explanation and I really appreciate you going to the trouble to show an alternate method as well as the trivial case.
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      1. USspinlock
 

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