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POPython timing - There must be a better way!
 

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    <p>I hope someone can help me out with this. I'd like to measure sorting algorithms. Here's how I currently do it:</p> <pre><code>M = 1000 # number of executions N = [1000, 2000, 4000, 16000] # size of the list L = [100, 1000, 2000,16000] # max element of the list # timing: print 'Number of executions: %i' % (M) print '-'*80 print '\tL\N\t|\t%i\t|\t%i\t|\t%i\t|\t%i' % (N[0], N[1], N[2], N[3]) print '-'*80 for l in L: print '\t%i\t' % l, for n in N: t = 0 for m in xrange(M): A = [random.randint(0,l-1) for r in xrange(n)] # generates an n long random list t0 = time.clock() pass # sort function call goes here t1 = time.clock() t += (t1-t0) print '|\t%0.3f\t' % ((t*1000.0)/M ), # avg time print print '-'*80 </code></pre> <p>This empty test takes about 4 minutes. I would appreciate any advice on how to make it faster.</p> <p>Cheers</p> <p><strong>Edit:</strong> After Rafe Kettler's hint, I came up with this:</p> <pre><code>def sorting(LST): pass if __name__ == "__main__" : M = 1000 N = [1000, 2000, 4000, 16000] L = [100, 1000, 2000,16000] print 'Number of executions: %i' % (M) print '-'*80 print '\tL\N\t|\t%i\t|\t%i\t|\t%i\t|\t%i' % (N[0], N[1], N[2], N[3]) print '-'*80 for l in L: print '\t%i\t' % l, for n in N: #------------------------ t = timeit.Timer('sorting([random.randint(0,l-1) for r in xrange(n)])', 'from __main__ import sorting, n, l, random') #------------------------ print '|\t%0.3f\t' % (t.timeit(M)/M ), # avg time print print '-'*80 </code></pre> <p>Unfortunately it become slower. What am I doing wrong?</p>
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