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    <pre><code>void (*signal(int signo, void (*func)(int)))(int); </code></pre> <p>signal is function that takes int and a pointer to function taking int and returning void and returns a function pointer taking int and returning void. That is,</p> <pre><code>typedef void(*funcPtr)(int) </code></pre> <p>then we have</p> <pre><code>funcPtr signal(int signo, funcPtr func); //equivalent to the above </code></pre> <p>The syntax is indeed strange, and such things better be done with a typedef. As an example, if you want to declare a function that takes an int and returns a pointer to a function taking char and returning double will be</p> <pre><code>double (*f(int))(char); </code></pre> <p><strong>Edit:</strong> after a comment that reads "Wooooooow", I am providing another example which is more "woooow" :)</p> <p>Let's declare a function that takes<br> 1. a pointer to array of 5 pointers to functions each taking float and returning double.<br> 2. a pointer to array of 3 ponters to arrays of 4 ints<br> and returns a pointer to function that takes a pointer to function taking int and returning a pointer to function taking float and returning void and returns unsigned int. </p> <p>The typedef solution would be this:</p> <pre><code>typedef double (*f1ptr) (float); typedef f1ptr (*arr1ptr)[5]; typedef int (*arr2ptr)[4]; typedef arr2ptr (*arr3ptr)[3]; typedef void(*f2Ptr)(float); typedef f2ptr (*f3ptr)(int); typedef unsigned int (*f4ptr) (f3ptr); f4ptr TheFunction(arr1ptr arg1, arr3ptr arg2); </code></pre> <p>Now, the funny part :) <strong>Without typedefs this will be</strong>:</p> <pre><code> unsigned int (*TheFunction( double (*(*)[5])(float), int(*(*)[3])[4]))( void(*(*)(int))(float)) </code></pre> <p>My god, did I just write that? :)</p>
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    1. USArmen Tsirunyan
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    1. COWooooooooooooow
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    2. CO@valdo: see my edit for a worse wooooow :)
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    3. COFunny? The non-typedef'd version is *perfectly* transparent.
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