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    <p>Interesting question... One plain JavaScript solution is to create an index for your objects in a separate array, based on the <code>'Surname'</code> property. Something like this<sup>1</sup>:</p> <pre><code>var peopleobj = { "0291" : { "Forename" : "Jeremy", "Surname" : "Dyson" }, "0398" : { "Forename" : "Billy", "Surname" : "Bunter" }, "6714" : { "Forename" : "Harry", "Surname" : "Peterson" }, "9080" : { "Forename" : "Barry", "Surname" : "Mainwaring" } }; var index = []; // build the index for (var x in peopleobj) { index.push({ 'key': x, 'Surname': peopleobj[x]['Surname'] }); } // sort the index index.sort(function (a, b) { var as = a['Surname'], bs = b['Surname']; return as == bs ? 0 : (as &gt; bs ? 1 : -1); }); </code></pre> <p>Now you would be able to iterate over your <code>index</code> array:</p> <pre><code>for (var i = 0; i &lt; index.length; i++) { console.log(peopleobj[index[i]['key']]['Surname']); } </code></pre> <p>Result (Tested in Firebug console):</p> <pre><code>Bunter Dyson Mainwaring Peterson </code></pre> <p>You may want to wrap this up into some sort of reusable Iterator object, even though it would be difficult to get as terse as Perl:</p> <pre><code>// Our reusable Iterator class: function MyIterator (o, key) { this.index = []; this.i = 0; this.o = o; for (var x in o) { this.index.push({ 'key': x, 'order': o[x][key] }); } this.index.sort(function (a, b) { var as = a['order'], bs = b['order']; return as == bs ? 0 : (as &gt; bs ? 1 : -1); }); this.len = this.index.length; } MyIterator.prototype.next = function () { return this.i &lt; this.len ? this.o[this.index[this.i++]['key']] : null; }; </code></pre> <p>Then use it as follows:</p> <pre><code>// Our JavaScript object: var peopleobj = { "0291" : { "Forename" : "Jeremy", "Surname" : "Dyson" }, "0398" : { "Forename" : "Billy", "Surname" : "Bunter" }, "6714" : { "Forename" : "Harry", "Surname" : "Peterson" }, "9080" : { "Forename" : "Barry", "Surname" : "Mainwaring" } }; // Build the Iterator object, using the 'Surname' field: var surnameIter = new MyIterator(peopleobj, 'Surname'); // Iterate: var i; while (i = surnameIter.next()) { console.log(i['Surname'] + ' ' + i['Forename']); } </code></pre> <p>Result: </p> <pre><code>Bunter Billy Dyson Jeremy Mainwaring Barry Peterson Harry </code></pre> <hr> <p><sup>1</sup> You may want to use the <a href="https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Object/hasOwnProperty" rel="noreferrer"><code>hasOwnProperty()</code></a> method to ensure that the properties belong to your object and are not inherited from <code>Object.prototype</code>:</p> <pre><code>for (var x in peopleobj) { if (peopleobj.hasOwnProperty(x)) { index.push({ 'key': x, 'Surname': peopleobj[x]['Surname'] }); } } </code></pre>
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    1. POIterating over a JavaScript object in sort order based on particular key value of a child object
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    1. CO+1. Good answer, although the comparison function passed to `sort()` is supposed to return a number, not a Boolean. I'd suggest something like `function (a, b) { var as = a.Surname., bs = b.Surname; return as == bs ? 0 : (as > bs ? 1 : -1); }`
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    2. CO@Tim: Thanks, you're right. I'll update my answer.
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    3. COThis is a great solution thanks for the explanation. I used this plus converted string to Date in the sort functions and got exactly what I needed.
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