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    <p><strong>overloadSetter</strong></p> <p><code>overloadSetter</code>, together with <code>overloadGetter</code>, are two function decorator methods. The <code>overloadSetter</code> function is used to transform functions that have the signature <code>fn(key, value)</code> to functions that could accept object arguments, ie: <code>fn({key: value})</code>.</p> <p>In order to do this, <code>overloadSetter</code> must wrap the original function. This wrapper function has the signature <code>fn(a, b)</code> which is a shortcut for <code>fn(key, value)</code>. This effectively becomes the new overloaded version of the original function.</p> <p>First thing this overloaded function does is check whether the passed <code>key</code> argument (<code>a</code>) is of the string type or not. If it's not a string, the function assumes that we're passing an object. So it iterates over each key-value pair in the object and applies the original function to it. If it's a string, on the other hand, it simply applies the function to the values of the <code>a</code> and <code>b</code> arguments.</p> <p><strong>Example</strong></p> <p>To illustrate, let's say we have the following function:</p> <pre><code>var fnOrig = function(key, value){ console.log(key + ': ' + value); }; var fnOver = fnOrig.overloadSetter(); fnOver('fruit', 'banana'); fnOver({'fruit': 'banana', 'vegetable': 'carrot'}); </code></pre> <p>In the first invocation, the <code>fnOver</code> function is invoked with two arguments, a key and a value. When the function checks the type of the <code>a</code> argument value, it'll see that it is a string. Therefore, it will simply invoke the original <code>fnOrig</code> function: <code>fnOrig.call(this, 'fruit', 'banana')</code>. Our console output is <code>'fruit: banana'</code>.</p> <p>For the second invocation, the <code>fnOver</code> function is invoked with an object argument. Since we passed an object instead of a string, <code>fnOver</code> will iterate through the members of this object and invoke the <code>fnOrig</code> function for each one of them. Thus, <code>fnOrig</code> will be invoked twice in this case: <code>fnOrig.call(this, 'fruit', 'banana')</code> and <code>fnOrig.call(this, 'vegetable', 'carrot')</code>. Our console output is <code>'fruit: banana'</code> and <code>'vegetable: carrot'</code>.</p> <p><strong>Extras</strong></p> <p>Inside the wrapper function, you'll see that there's an check for the value of <code>usePlural</code>. This is an argument for the <code>overloadSetter</code> method itself. If you set this value to <code>true</code>, the new function will treat all arguments as object. This means that even if you pass a string key argument, it will still be processed as an object.</p> <p>The other thing, the <code>enumerables</code> code that preludes the actual method declaration, is there because it fixes an issue with some browsers wherein the native <code>Object</code> methods are not enumerated in <code>for/in</code> loops even if the object itself implements its own version of it.</p>
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    1. POWhat does MooTools' Function.prototype.overloadSetter() do?
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    1. USMark Keeto Obcena
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    1. POWhat does MooTools' Function.prototype.overloadSetter() do?
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    1. COalthough this is _somewhat unlikely_ to change, i should point out that this is a private / internal method and writing code that depends on the API may not stand the test of time (works in 1.3 for the time being)
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      1. USDimitar Christoff
    2. COundocumented, so no promises. use at your own risk :)
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      1. USseanmonstar
    3. COThanks for the great answer. @Dimitar, seanmonstar: That's OK, I'm not planning on using it, I just wanted to understand how the function worked and what it did.
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      1. USAustin Hyde
 

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