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PODoes this simple Haskell function already have a well-known name?
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Id
3998133
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AcceptedAnswerId
3998320
AnswerCount
4
ClosedDate
CommentCount
2
CommunityOwnedDate
CreationDate
2010-10-22T15:04:32.820
FavoriteCount
1
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2012-05-03T18:59:41.193
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2012-05-03T18:59:41.193
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8
ViewCount
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text
Body
I've just written this function which simply takes a pair whose second value is in some monad, and "pulls the monad out" to cover the whole pair. <pre><code>unSndM :: Monad m => (a, m c) -> m (a, c) unSndM (x, y) = do y' <- y return (x, y') </code></pre> Is there a nicer and/or shorter or point-free or even standard way to express this? I've got as far as the following, with -XTupleSections turned on... <pre><code>unSndM' :: Monad m => (a, m c) -> m (a, c) unSndM' (x, y) = y >>= return . (x,) </code></pre> Thanks!
Tags
<haskell><tuples><monads>
Title
Does this simple Haskell function already have a well-known name?
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1. PO
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1. PTQuestion
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1. USBruce
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1. USgimboland
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2. VO
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1. CORules of tag `code-golf`: http://stackoverflow.com/tags/code-golf/info
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 PODoes this simple Haskell function already have a well-known name?
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 USNakilon
2. COFair enough. The site let me add the tag without telling me there were rules associated with it. *shrug*
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 PODoes this simple Haskell function already have a well-known name?
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 USgimboland

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