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POHow to convert an 8-bit OpenCV IplImage* to a 32-bit IplImage*?
 

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  1. POHow to convert an 8-bit OpenCV IplImage* to a 32-bit IplImage*?
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    <p>I need to convert an 8-bit IplImage to a 32-bits IplImage. Using documentation from all over the web I've tried the following things:</p> <pre><code>// general code img2 = cvCreateImage(cvSize(img-&gt;width, img-&gt;height), 32, 3); int height = img-&gt;height; int width = img-&gt;width; int channels = img-&gt;nChannels; int step1 = img-&gt;widthStep; int step2 = img2-&gt;widthStep; int depth1 = img-&gt;depth; int depth2 = img2-&gt;depth; uchar *data1 = (uchar *)img-&gt;imageData; uchar *data2 = (uchar *)img2-&gt;imageData; for(h=0;h&lt;height;h++) for(w=0;w&lt;width;w++) for(c=0;c&lt;channels;c++) { // attempt code... } // attempt one // result: white image, two red spots which appear in the original image too. // this is the closest result, what's going wrong?! // see: http://files.dazjorz.com/cache/conversion.png ((float*)data2+h*step2+w*channels+c)[0] = data1[h*step1+w*channels+c]; // attempt two // when I change float to unsigned long in both previous examples, I get a black screen. // attempt three // result: seemingly random data to the top of the screen. data2[h*step2+w*channels*3+c] = data1[h*step1+w*channels+c]; data2[h*step2+w*channels*3+c+1] = 0x00; data2[h*step2+w*channels*3+c+2] = 0x00; // and then some other things. Nothing did what I wanted. I couldn't get an output // image which looked the same as the input image. </code></pre> <p>As you see I don't really know what I'm doing. I'd love to find out, but I'd love it more if I could get this done correctly. Thanks for any help I get!</p>
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