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    <p>Since <code>500!</code> equals <code>1220136825991110068701238785423046926253574342803192842192413588385845373153881997605496447502203281863013616477148203584163378722078177200480785205159329285477907571939330603772960859086270429174547882424912726344305670173270769461062802310452644218878789465754777149863494367781037644274033827365397471386477878495438489595537537990423241061271326984327745715546309977202781014561081188373709531016356324432987029563896628911658974769572087926928871281780070265174507768410719624390394322536422605234945850129918571501248706961568141625359056693423813008856249246891564126775654481886506593847951775360894005745238940335798476363944905313062323749066445048824665075946735862074637925184200459369692981022263971952597190945217823331756934581508552332820762820023402626907898342451712006207714640979456116127629145951237229913340169552363850942885592018727433795173014586357570828355780158735432768888680120399882384702151467605445407663535984174430480128938313896881639487469658817504506926365338175055478128640000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000</code> you can't fit it into an <code>int</code> (which ranges up to <code>2147483647</code>).</p> <ul> <li>Using an <code>int</code> you can only store up to <code>12!</code>.</li> <li>Using a <code>long</code> you'll get up to <code>20!</code></li> <li>Using a <code>double</code> you'll get up to <code>170!</code>.</li> </ul> <p>Here is a solution using <code>BigInteger</code>:</p> <pre><code>public static BigInteger factorial(int i) { BigInteger n = BigInteger.valueOf(i); while (--i &gt; 0) n = n.multiply(BigInteger.valueOf(i)); return n; } </code></pre>
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    1. POfactorial method doesn't work well!
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    1. COThanks a lot for your answer! :)
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    2. COTo improve performance, you could also check i first and switch to BigInteger if needed ^^!
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    3. COThat would be a minor improvement, as it only optimizes the method for really small input-values.
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