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    <p>The following works fine for me in Firefox and IE8:</p> <pre><code>&lt;html&gt; &lt;body&gt; &lt;script type="text/javascript"&gt; // MAYBE FORGOT THIS PART? var xmlhttp = new XMLHttpRequest(); xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4) { document.write(xmlhttp.responseText); } } // THIS PART IS EXACTLY LIKE YOURS var params = "type=search" + "&amp;content="+encodeURIComponent(document.getElementsByTagName("body")[0].innerHTML); xmlhttp.open("POST", "/service/p.aspx", true); xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xmlhttp.setRequestHeader("Content-length", params.length); xmlhttp.send(params); &lt;/script&gt; &lt;/body&gt; &lt;/html&gt; </code></pre> <p>Perhaps you just forgot to declare <code>xmlhttp</code> and add a listener for the asynchronous status callback?</p> <hr> <p>Also, see <a href="https://stackoverflow.com/questions/415160/best-method-of-instantiating-an-xmlhttprequest-object">this SO question</a> for more information about getting an <code>XMLHttpRequest</code> object in a cross-browser fashion.</p> <hr> <p>Here is what is being sent in the POST request via FireBug in Firefox:</p> <pre><code>type=search&amp;content=%0A%20%20%20%20%20%20%20%20%3Cscript%20type%3D%22text%2Fjavascript%22%3E%0A%2F%2F%20MAYBE%20FORGOT%20THIS%20PART%3F%0Avar%20xmlhttp%20%3D%20new%20XMLHttpRequest()%3B%0Axmlhttp.onreadystatechange%3Dfunction()%0A%7B%0A%20%20%20%20if%20(xmlhttp.readyState%3D%3D4)%0A%20%20%20%20%7B%0A%20%20%20%20%20%20%20%20document.write(xmlhttp.responseText)%3B%0A%20%20%20%20%7D%0A%7D%0A%0A%2F%2F%20THIS%20PART%20IS%20EXACTLY%20LIKE%20YOURS%0Avar%20params%20%3D%20%22type%3Dsearch%22%20%2B%20%22%26content%3D%22%2BencodeURIComponent(document.getElementsByTagName(%22body%22)%5B0%5D.innerHTML)%3B%0Axmlhttp.open(%22POST%22%2C%20%22%2Fservice%2Fp.aspx%22%2C%20true)%3B%0Axmlhttp.setRequestHeader(%22Content-type%22%2C%20%22application%2Fx-www-form-urlencoded%22)%3B%0Axmlhttp.setRequestHeader(%22Content-length%22%2C%20params.length)%3B%20%0Axmlhttp.send(params)%3B%0A%20%20%20%20%20%20%20%20%3C%2Fscript%3E </code></pre> <p>So you have <code>type</code> which equals <code>search</code>, and <code>content</code>, which is the HTTP-encoded <code>body</code> of the HTML above, exactly as programmed. So it seems to be working as intended...</p>
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    1. COhello jdmical, thnak you for your help , i declared the xmlhttp sorry for not include it in my question . i jus cant send the html page body content but i can send any thing else . thank you
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    2. CO@fligant I added the actual POST message to the answer. Please check.
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    3. COthank you jsmical it's worked i don't know whay!!! but it work :) thank you for your hellp
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