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POPython: Dictionary of list of lists
 

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    <pre><code>def makecounter(): return collections.defaultdict(int) class RankedIndex(object): def __init__(self): self._inverted_index = collections.defaultdict(list) self._documents = [] self._inverted_index = collections.defaultdict(makecounter) def index_dir(self, base_path): num_files_indexed = 0 allfiles = os.listdir(base_path) self._documents = os.listdir(base_path) num_files_indexed = len(allfiles) docnumber = 0 self._inverted_index = collections.defaultdict(list) docnumlist = [] for file in allfiles: self.documents = [base_path+file] #list of all text files f = open(base_path+file, 'r') lines = f.read() tokens = self.tokenize(lines) docnumber = docnumber + 1 for term in tokens: if term not in sorted(self._inverted_index.keys()): self._inverted_index[term] = [docnumber] self._inverted_index[term][docnumber] +=1 else: if docnumber not in self._inverted_index.get(term): docnumlist = self._inverted_index.get(term) docnumlist = docnumlist.append(docnumber) f.close() print '\n \n' print 'Dictionary contents: \n' for term in sorted(self._inverted_index): print term, '-&gt;', self._inverted_index.get(term) return num_files_indexed return 0 </code></pre> <p>I get index error on executing this code: list index out of range.</p> <p>The above code generates a dictionary index that stores the 'term' as a key and the document numbers in which the term occurs as a list. For ex: if the term 'cat' occurs in documents 1.txt, 5.txt and 7.txt the dictionary will have: cat &lt;- [1,5,7]</p> <p>Now, I have to modify it to add term frequency, so if the word cat occurs twice in document 1, thrice in document 5 and once in document 7: expected result: term &lt;-[[docnumber, term freq], [docnumber,term freq]] &lt;--list of lists in a dict!!! cat &lt;- [[1,2],[5,3],[7,1]]</p> <p>I played around with the code, but nothing works. I have no clue to modify this datastructure to achieve the above.</p> <p>Thanks in advance.</p>
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