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  1. PODamerau - Levenshtein Distance, adding a threshold
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    <p>I have the following implementation, but I want to add a threshold, so if the result is going to be greater than it, just stop calculating and return.</p> <p>How would I go about that?</p> <p>EDIT: Here is my current code, <code>threshold</code> is not yet used...the goal is that it is used</p> <pre><code> public static int DamerauLevenshteinDistance(string string1, string string2, int threshold) { // Return trivial case - where they are equal if (string1.Equals(string2)) return 0; // Return trivial case - where one is empty if (String.IsNullOrEmpty(string1) || String.IsNullOrEmpty(string2)) return (string1 ?? "").Length + (string2 ?? "").Length; // Ensure string2 (inner cycle) is longer if (string1.Length &gt; string2.Length) { var tmp = string1; string1 = string2; string2 = tmp; } // Return trivial case - where string1 is contained within string2 if (string2.Contains(string1)) return string2.Length - string1.Length; var length1 = string1.Length; var length2 = string2.Length; var d = new int[length1 + 1, length2 + 1]; for (var i = 0; i &lt;= d.GetUpperBound(0); i++) d[i, 0] = i; for (var i = 0; i &lt;= d.GetUpperBound(1); i++) d[0, i] = i; for (var i = 1; i &lt;= d.GetUpperBound(0); i++) { for (var j = 1; j &lt;= d.GetUpperBound(1); j++) { var cost = string1[i - 1] == string2[j - 1] ? 0 : 1; var del = d[i - 1, j] + 1; var ins = d[i, j - 1] + 1; var sub = d[i - 1, j - 1] + cost; d[i, j] = Math.Min(del, Math.Min(ins, sub)); if (i &gt; 1 &amp;&amp; j &gt; 1 &amp;&amp; string1[i - 1] == string2[j - 2] &amp;&amp; string1[i - 2] == string2[j - 1]) d[i, j] = Math.Min(d[i, j], d[i - 2, j - 2] + cost); } } return d[d.GetUpperBound(0), d.GetUpperBound(1)]; } } </code></pre>
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