StackOverflow2013

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plurals

PO
primarykey
Id
3796222
data
AcceptedAnswerId
0
AnswerCount
0
ClosedDate
CommentCount
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CreationDate
2010-09-26T01:20:56.220
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2010-09-26T01:30:44.623
LastEditDate
2010-09-26T01:30:44.623
LastEditorUserId
454638
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454638
ParentId
3796181
PostTypeId
2
Score
12
ViewCount
0
LastEditorDisplayName
text
Body
To declare a function that takes a pointer to an int: <code>void Foo(int *x);</code> To use this function: <pre><code> int x = 4; int *x_ptr = &x; Foo(x_ptr); Foo(&x); </code></pre> If you want a pointer for another type of object, it's much the same: <code>void Foo(Object *o);</code> But, you may prefer to use references. They are somewhat less confusing than pointers: <pre><code> // pass a reference void Foo(int &x) { x = 2; } //pass a pointer void Foo_p(int *p) { *x = 9; } // pass by value void Bar(int x) { x = 7; } int x = 4; Foo(x); // x now equals 2. Foo_p(&x); // x now equals 9. Bar(x); // x still equals 9. </code></pre> With references, you still get to change the x that was passed to the function (as you would with a pointer), but you don't have to worry about dereferencing or address of operations. As recommended by others, check out the <a href="http://www.parashift.com/c++-faq-lite/" rel="noreferrer">C++FAQLite</a>. It's an excellent resource for this. Edit 3 response: bar = &foo means: Make bar point to foo in memory Yes. *bar = foo means Change the value that bar points to to equal whatever foo equals Yes. If I have a second pointer (int *oof), then: bar = oof means: bar points to the oof pointer bar will point to whatever oof points to. They will both point to the same thing. bar = *oof means: bar points to the value that oof points to, but not to the oof pointer itself No. You can't do this (assuming bar is of type int *) You can make pointer pointers. (int **), but let's not get into that... You cannot assign a pointer to an int (well, you can, but that's a detail that isn't in line with the discussion). *bar = *oof means: change the value that bar points to to the value that oof points to Yes. &bar = &oof means: change the memory address that bar points to be the same as the memory address that oof points to No. You can't do this because the address of operator returns an rvalue. Basically, that means you can't assign something to it.
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1. This table or related slice is empty.
PostParentId
1. POC++ Passing Pointer to Function (Howto) + C++ Pointer Manipulation
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PostTypePostTypeId
1. PTAnswer
UserLastEditorUserId
1. USJoshD
UserOwnerUserId
1. USJoshD
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1. VO
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