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    <p><a href="http://lxml.de/" rel="nofollow noreferrer">lxml</a> is namespace-aware.</p> <pre><code>&gt;&gt;&gt; from lxml import etree &gt;&gt;&gt; et = etree.XML("""&lt;root xmlns="foo" xmlns:stuff="bar"&gt;&lt;bar&gt;&lt;stuff:baz /&gt;&lt;/bar&gt;&lt;/root&gt;""") &gt;&gt;&gt; etree.tostring(et, encoding=str) # encoding=str only needed in Python 3, to avoid getting bytes '&lt;root xmlns="foo" xmlns:stuff="bar"&gt;&lt;bar&gt;&lt;stuff:baz/&gt;&lt;/bar&gt;&lt;/root&gt;' &gt;&gt;&gt; et.xpath("f:bar", namespaces={"b":"bar", "f": "foo"}) [&lt;Element {foo}bar at ...&gt;] </code></pre> <p>Edit: On your example:</p> <pre><code>from lxml import etree # remove the b prefix in Python 2 # needed in python 3 because # "Unicode strings with encoding declaration are not supported." et = etree.XML(b"""...""") ns = { 'lom': 'http://ltsc.ieee.org/xsd/LOM', 'zs': 'http://www.loc.gov/zing/srw/', 'dc': 'http://purl.org/dc/elements/1.1/', 'voc': 'http://www.schooletc.co.uk/vocabularies/', 'srw_dc': 'info:srw/schema/1/dc-schema' } # according to docs, .xpath returns always lists when querying for elements # .find returns one element, but only supports a subset of XPath record = et.xpath("zs:records/zs:record", namespaces=ns)[0] # in this example, we know there's only one record # but else, you should apply the following to all elements the above returns name = record.xpath("//voc:name", namespaces=ns)[0].text print("name:", name) lom_entry = record.xpath("zs:recordData/srw_dc:dc/" "lom:metaMetadata/lom:identifier/" "lom:entry", namespaces=ns)[0].text print('lom_entry:', lom_entry) lom_ids = [id.text for id in record.xpath("zs:recordData/srw_dc:dc/" "lom:classification/lom:taxonPath/" "lom:taxon/lom:id", namespaces=ns)] print("lom_ids:", lom_ids) </code></pre> <p>Output:</p> <pre><code>name: Frank Malina lom_entry: 2.6 lom_ids: ['PYTHON', 'XML', 'XML-NAMESPACES'] </code></pre>
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    1. POGood python XML parser to work with namespace heavy documents
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    1. POGood python XML parser to work with namespace heavy documents
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    1. CO+1 lxml is the only python tool/package you'll ever need for xml/xslt/xpath related tasks
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    2. COEdit: How would you code around the example provided? The lack of recipes on the web for this sort of lxml work is appalling. At the moment, I have proceeded by stripping the namespaces and traversing with BeautifulSoup. This is suboptimal on a number of levels.
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    3. CO@Frank Malina: XPath isn't lxml-specific, there are some useable ressources on XPath across the web. But I will make a stab at it...
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