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primarykey
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3759413
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0
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2010-09-21T10:30:40.897
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2010-09-21T10:39:26.513
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2010-09-21T10:39:26.513
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398968
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3759200
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2
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text
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<pre><code>with open("xmlbasic.txt") as lines_file: lines = lines_file.read() import xml.etree.ElementTree as ET root = ET.Element('root') for line in lines: head, subhead, tail = line.split(":") head_branch = root.find(head) if not head_branch: head_branch = ET.SubElement(root, head) subhead_branch = head_branch.find(subhead) if not subhead_branch: subhead_branch = ET.SubElement(branch1, subhead) subhead_branch.text = tail tree = ET.ElementTree(root) ET.dump(tree) </code></pre> The logic is simple -- you already stated it in your question! You merely need to check whether a branch already exists in the tree before creating it. Note that this is likely inefficient, since you are searching up to the entire tree for each line. This is because <code>ElementTree</code> is not designed for uniqueness. <hr> If you require speed (which you may not, especially for smallish trees!), a more efficient way would be to use a <code>defaultdict</code> to store the tree structure before converting it to an <code>ElementTree</code>. <pre><code>import collections import xml.etree.ElementTree as ET with open("xmlbasic.txt") as lines_file: lines = lines_file.read() root_dict = collections.defaultdict( dict ) for line in lines: head, subhead, tail = line.split(":") root_dict[head][subhead] = tail root = ET.Element('root') for head, branch in root_dict.items(): head_element = ET.SubElement(root, head) for subhead, tail in branch.items(): ET.SubElement(head_element,subhead).text = tail tree = ET.ElementTree(root) ET.dump(tree) </code></pre>
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1. POcreating xml tree from a textfile with Python
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1. PTAnswer
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1. USKatriel
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1. USKatriel
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1. POcreating xml tree from a textfile with Python
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1. COThanks, this and also other answers work fine, but I'll stick to defaultdict as in reality the text and xml files be rather big.
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