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2010-09-21T10:08:01.117
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2010-09-21T10:08:01.117
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I wrote an extension method for this purpose which works on any <code>IEnumerable<T></code>. <pre><code>/// <summary> /// Splits the specified IEnumerable at every element that satisfies a /// specified predicate and returns a collection containing each sequence /// of elements in between each pair of such elements. The elements /// satisfying the predicate are not included. /// </summary> /// <param name="splitWhat">The collection to be split.</param> /// <param name="splitWhere">A predicate that determines which elements /// constitute the separators.</param> /// <returns>A collection containing the individual pieces taken from the /// original collection.</returns> public static IEnumerable<IEnumerable<T>> Split<T>( this IEnumerable<T> splitWhat, Func<T, bool> splitWhere) { if (splitWhat == null) throw new ArgumentNullException("splitWhat"); if (splitWhere == null) throw new ArgumentNullException("splitWhere"); return splitIterator(splitWhat, splitWhere); } private static IEnumerable<IEnumerable<T>> splitIterator<T>( IEnumerable<T> splitWhat, Func<T, bool> splitWhere) { int prevIndex = 0; foreach (var index in splitWhat .Select((elem, ind) => new { e = elem, i = ind }) .Where(x => splitWhere(x.e))) { yield return splitWhat.Skip(prevIndex).Take(index.i - prevIndex); prevIndex = index.i + 1; } yield return splitWhat.Skip(prevIndex); } </code></pre> For example, in your case, you can use it like this: <pre><code>var arr = new string[] { "foo", "bar", "jar", "\r", "a", "b", "c", "\r", "x", "y", "z", "\r" }; var results = arr.Split(elem => elem == "\r"); foreach (var result in results) Console.WriteLine(string.Join(", ", result)); </code></pre> This will print: <pre><code>foo, bar, jar a, b, c x, y, z </code></pre> (including a blank line at the end, because there is a <code>"\r"</code> at the end of your collection).
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