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    <p>I already know how to catch standard output of a console window, BUT my problem is the case when I get the process with GetProcesses/orByName and do not Start() it myself. Here is the code:</p> <pre><code>public ProcessCaller(ISynchronizeInvoke isi, Process MárFutóAlkalmazás) : this(isi) { //alapbeállítások FileName = MárFutóAlkalmazás.StartInfo.FileName; Arguments = MárFutóAlkalmazás.StartInfo.Arguments; WorkingDirectory = MárFutóAlkalmazás.StartInfo.WorkingDirectory; //egyedi beállítások process = MárFutóAlkalmazás; process.EnableRaisingEvents = true; process.StartInfo.CreateNoWindow = true; process.StartInfo.UseShellExecute = false; process.StartInfo.RedirectStandardOutput = true; process.StartInfo.RedirectStandardError = true; new MethodInvoker(ReadStdOut).BeginInvoke(null, null); new MethodInvoker(ReadStdErr).BeginInvoke(null, null); //események StdErrReceived += new DataReceivedHandler(Loggolás); StdOutReceived += new DataReceivedHandler(Loggolás); //kilépés jelzése process.Exited += new EventHandler(OnKilépés); } </code></pre> <p>So this method gets and already running application as MárFutóAlkalmazás parameter. Sets some internal properties, then hooks to Output. However when it comes to</p> <pre><code>StdOutReceived += new DataReceivedHandler(Loggolás); </code></pre> <p>and the program runs the Loggolás method to take the console data, it says that the StandardOut is not set, or the process is not started.</p> <p>Well:</p> <ul> <li>StandardOut is set</li> <li>Process is running, since I get it by GetProcesses</li> <li>In this routine I do NOT use process.Start() - since it is started already</li> </ul> <p>Looking for help. Thank yas: Péter</p>
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    1. CO+1: Excellent first question, very well asked. We need more new users like you :)
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    2. COpossible duplicate of [Capture output from unrelated process](http://stackoverflow.com/questions/429225/capture-output-from-unrelated-process)
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    3. COI checked that "Capture output from unrelated process" you suggested, and after modifying the code there I got the same error message: the StandardOut (no such property BTW, only StandardOutput) is not set, or the process is not started.
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