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POReference vs. value copy for PHP arrays?
 

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  1. POReference vs. value copy for PHP arrays?
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    <p>I am missing something obvious. Here's a trivial piece of PHP, littered with debug echos:</p> <pre><code>function echo_rows(&amp;$res) { $rows= array(); while ($row= $res-&gt;fetch()) { echo $row['ccorID'] . "\r\n"; $rows[]= $row; echo $rows[0]['ccorID'] . "\r\n"; } echo "---.---\r\n"; echo count($rows) . "\r\n"; foreach($rows as $row) { echo $row['ccorID'] . "\r\n"; } echo json_encode($rows); } </code></pre> <p>Here's what I see in the response:</p> <pre><code>0 0 3 3 13 13 182 182 ---.--- 4 182 182 182 182 </code></pre> <p>It seems perfectly clear to me that :-</p> <ul> <li>I have 4 rows of data</li> <li><code>$rows[]= $row;</code> does NOT perform a value copy, despite what it says here <a href="http://uk.php.net/manual/en/language.types.array.php" rel="nofollow noreferrer">http://uk.php.net/manual/en/language.types.array.php</a></li> </ul> <p>Anyone got any idea what I need to do to get a copy of $row (which is an associative array)?</p> <p>Thanks.</p> <p>EDIT: Since many of you are so insistent to know what $res is, here is the class. I genuinely believe that this is more likely to confuse than enlighten (hence the omission from my OP).</p> <pre><code>class mysqlie_results { private $stmt; private $paramArray= array(); private $assocArray= array(); public function __construct(&amp;$stmt) { $this-&gt;stmt= $stmt; $meta= $stmt-&gt;result_metadata(); while ($colData= $meta-&gt;fetch_field()) { $this-&gt;paramArray[]= &amp;$this-&gt;assocArray[$colData-&gt;name]; } call_user_func_array(array($stmt,'bind_result'),$this-&gt;paramArray); $meta-&gt;close(); } public function __destruct() { $this-&gt;stmt-&gt;free_result(); } public function fetch() { return $this-&gt;stmt-&gt;fetch()? $this-&gt;assocArray : false; } } </code></pre>
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    1. COYou're right. It does not perform a value copy. It performs a variable copy. So if the variable is a reference, the resulting array element will be a reference as well... If it's not a reference, it will perform the value copy (just like any other variable copy)... And the value copy bit you cite is when you copy the entire element, not inserting records...
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    2. COPlease rename your title!
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    3. COFor some reason the first element of `$rows` is being overwritten here.
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      1. USBoltClock
 

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