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    <p>If you have the <code>rename</code> command on your UNIX, you should be able to use something like:</p> <pre><code>mkdir images_renamed cd images_renamed cp ../103*.jpg . rename 103 201003 *.jpg </code></pre> <p>The <code>rename FROM TO FILE</code> will rename all the files specified by <code>FILE</code>, changing the first occurrence of <code>FROM</code> to <code>TO</code>.</p> <p>If that's not available, you can use something like:</p> <pre><code>mkdir images_renamed for fspec in 103*.jpg ; do cp ${fspec} images_renamed/201003${fspec:3} done </code></pre> <p>To do this recursively, I would put it into a script with <code>find</code>:</p> <pre><code>#!/usr/bin/bash rm -rf images_renamed ls -lR images echo cd images find . -name '*.jpg' | while read -r; do mkdir -p "../images_renamed/$(dirname "$REPLY")" echo 'Copying from' [$REPLY] echo ' to' [../images_renamed/$REPLY] and renaming. echo cp "$REPLY" "../images_renamed/$REPLY" cd "$(dirname "../images_renamed/$REPLY")" rename 103 201003 "$(basename "$REPLY")" cd - &gt;/dev/null done cd .. ls -lR images_renamed </code></pre> <p>Only the middle bit of that is required, the rest is for testing. The output below shows how it works, copying across every file to the new directory structure and renaming the relevant files.</p> <pre><code>images: total 0 drwxr-xr-x+ 1 pax None 0 2010-08-12 20:55 dir1 drwxr-xr-x+ 1 pax None 0 2010-08-12 20:55 dir2 drwxr-xr-x+ 1 pax None 0 2010-08-12 20:56 dir3 images/dir1: total 0 -rw-r--r-- 1 pax None 0 2010-08-12 20:55 102xxx.jpg -rw-r--r-- 1 pax None 0 2010-08-12 20:55 103xxx.jpg images/dir2: total 0 -rw-r--r-- 1 pax None 0 2010-08-12 20:55 103yyy.jpg images/dir3: total 0 drwxr-xr-x+ 1 pax None 0 2010-08-12 20:55 dir 4 images/dir3/dir 4: total 0 -rw-r--r-- 1 pax None 0 2010-08-12 20:55 103zzz.jpg Copying from [./dir1/102xxx.jpg] to [../images_renamed/./dir1/102xxx.jpg] and renaming. Copying from [./dir1/103xxx.jpg] to [../images_renamed/./dir1/103xxx.jpg] and renaming. Copying from [./dir2/103yyy.jpg] to [../images_renamed/./dir2/103yyy.jpg] and renaming. Copying from [./dir3/dir 4/103zzz.jpg] to [../images_renamed/./dir3/dir 4/103zzz.jpg] and renaming. images_renamed: total 0 drwxr-xr-x+ 1 pax None 0 2010-08-12 21:19 dir1 drwxr-xr-x+ 1 pax None 0 2010-08-12 21:19 dir2 drwxr-xr-x+ 1 pax None 0 2010-08-12 21:19 dir3 images_renamed/dir1: total 0 -rw-r--r-- 1 pax None 0 2010-08-12 21:19 102xxx.jpg -rw-r--r-- 1 pax None 0 2010-08-12 21:19 201003xxx.jpg images_renamed/dir2: total 0 -rw-r--r-- 1 pax None 0 2010-08-12 21:19 201003yyy.jpg images_renamed/dir3: total 0 drwxr-xr-x+ 1 pax None 0 2010-08-12 21:19 dir 4 images_renamed/dir3/dir 4: total 0 -rw-r--r-- 1 pax None 0 2010-08-12 21:19 201003zzz.jpg </code></pre> <hr> <p>To flatten the file hierarchy, you can use something like:</p> <pre><code>#!/usr/bin/bash rm -rf images_renamed ls -lR images echo cd images mkdir -p ../images_renamed find . -name '*.jpg' | while read -r; do newfile="$(basename "$REPLY")" echo 'Copying from' [$REPLY] echo ' to' [../images_renamed/$newfile] and renaming. echo cp "$REPLY" "../images_renamed/$newfile" cd ../images_renamed rename 103 201003 "$newfile" cd - &gt;/dev/null done </code></pre> <p>which outputs:</p> <pre><code>cd .. ls -lR images_renamed images: total 0 drwxr-xr-x+ 1 allan None 0 2010-08-12 20:55 dir1 drwxr-xr-x+ 1 allan None 0 2010-08-12 20:55 dir2 drwxr-xr-x+ 1 allan None 0 2010-08-12 20:56 dir3 images/dir1: total 0 -rw-r--r-- 1 allan None 0 2010-08-12 20:55 102xxx.jpg -rw-r--r-- 1 allan None 0 2010-08-12 20:55 103xxx.jpg images/dir2: total 0 -rw-r--r-- 1 allan None 0 2010-08-12 20:55 103yyy.jpg images/dir3: total 0 drwxr-xr-x+ 1 allan None 0 2010-08-12 20:55 dir 4 images/dir3/dir 4: total 0 -rw-r--r-- 1 allan None 0 2010-08-12 20:55 103zzz.jpg Copying from [./dir1/102xxx.jpg] to [../images_renamed/102xxx.jpg] and renaming. Copying from [./dir1/103xxx.jpg] to [../images_renamed/103xxx.jpg] and renaming. Copying from [./dir2/103yyy.jpg] to [../images_renamed/103yyy.jpg] and renaming. Copying from [./dir3/dir 4/103zzz.jpg] to [../images_renamed/103zzz.jpg] and renaming. images_renamed: total 0 -rw-r--r-- 1 allan None 0 2010-08-12 22:41 102xxx.jpg -rw-r--r-- 1 allan None 0 2010-08-12 22:41 201003xxx.jpg -rw-r--r-- 1 allan None 0 2010-08-12 22:41 201003yyy.jpg -rw-r--r-- 1 allan None 0 2010-08-12 22:41 201003zzz.jpg </code></pre> <p>but you need to keep in mind that filename clashes (the same file name under different directories) will overwrite each other.</p>
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    1. POBatch renaming files using UNIX - should I use awk?
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    1. POBatch renaming files using UNIX - should I use awk?
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    1. CODoes this work recursively?
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    2. CONo, you need a find wrapped around it. Updated to show one way of doing it.
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    3. COThanks for your answer. The only thing I would want to change is the destination. Instead of retaining the directory structure where the files were copied from - I want all the images to be copied to the 'images_renamed' folder. I've tried changing the script you provided but no sucess. I cant work out the relationship between $REPLY and dirname, basename etc. I can tell that $REPLY is the ful path and filename that the find command matches - but can I extract only the filename from this information for use in the rename step (ie. using only the filename, not the directory)
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