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POPass href dynamically in an XML file
 

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    <p>How can I dynamically specify the href value in the line</p> <pre><code>&lt;?xml-stylesheet type="text/xsl" href="first.xsl"?&gt; </code></pre> <p>in an xml? </p> <p>I would like to substitute "first.xsl" dynamically.</p> <p>Thanks for your help. ================== Apologies for messing this up/making it difficult for you to help ====</p> <p>My XML is:</p> <pre><code>&lt;?xml version="1.0" encoding="utf-8"?&gt; &lt;?xml-stylesheet type="text/xsl" href="first.xsl"?&gt; &lt;WinData records="1" fields="4"&gt; &lt;record id="1"&gt; &lt;Name type="82"&gt;January&lt;/Name&gt; &lt;Dept type="323"&gt;19&lt;/Dept&gt; &lt;InceptionDate type="82"&gt;01/01/2010&lt;/InceptionDate&gt; &lt;Salary type="645"&gt;3729.71&lt;/Salary&gt; &lt;/record&gt; &lt;!-- Created from D:\AJAY\C#\VS2010\SBWA\XML --&gt; &lt;/WinData&gt; </code></pre> <p>The XSL is:</p> <pre><code>&lt;?xml version="1.0" encoding="ISO-8859-1"?&gt; &lt;!-- Edited by XMLSpy® --&gt; &lt;xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt; &lt;xsl:template match="/"&gt; &lt;html&gt; &lt;body&gt; &lt;h2&gt;Sub Selection of Data&lt;/h2&gt; &lt;table border="0"&gt; &lt;tr bgcolor="#9acd32"&gt; &lt;th&gt;Name&lt;/th&gt; &lt;th&gt;Dept&lt;/th&gt; &lt;th&gt;InceptionDate&lt;/th&gt; &lt;th&gt;Salary&lt;/th&gt; &lt;/tr&gt; &lt;xsl:for-each select="WinData/record" &gt; &lt;xsl:sort select="./Name"/&gt; &lt;xsl:sort select="./Dept"/&gt; &lt;xsl:if test="Salary&gt;100"&gt; &lt;tr&gt; &lt;td&gt;&lt;xsl:value-of select="Name"/&gt;&lt;/td&gt; &lt;td&gt;&lt;xsl:value-of select="Dept"/&gt;&lt;/td&gt; &lt;td&gt;&lt;xsl:value-of select="InceptionDate"/&gt;&lt;/td&gt; &lt;td&gt;&lt;xsl:value-of select="Salary"/&gt;&lt;/td&gt; &lt;/tr&gt; &lt;/xsl:if&gt; &lt;/xsl:for-each&gt; &lt;/table&gt; &lt;/body&gt; &lt;/html&gt; &lt;/xsl:template&gt; &lt;/xsl:stylesheet&gt; </code></pre> <p>My specific issues/objectives:</p> <ol> <li>How can I incorporate the code snippet offerred by iHeartGreek?</li> <li>Is there a way to pass the 'replacement' xsl (newLink.xsl in the snippet) as a parameter?</li> </ol>
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    1. COThe line I pasted doe not show href="first.xsl"
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    2. COThere is an option to turn text into code (which will make sure that code-like text indeed shows up). The button is on the formatting bar which has a bunch of binary on it.
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    3. COIf you post code or XML, **please** highlight those lines in the text editor and click on the "code" button (101 010) on the editor toolbar to nicely format and syntax highlight it!
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