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    <p>First you need to be explicit about the replacement conditions, your rules say 'not at the begining of a word and not before/after a vowel' but you have not implemented that in the regex. You can do this using Negative Lookahead/Lookbehind. For example:</p> <ol> <li>Replace a, i, o with u (if not at the beginning of a word &amp; if not before/after a vowel)</li> </ol> <p>Can be implemented with:</p> <pre><code>$patterns[] = "/(?&lt;!\b|[aeiou])[aio](?![aeiou])/"; $replacements[] = "u"; </code></pre> <p>This method can be used to implement the first 3 rules.</p> <p>The next problem is that 'fox' and 'dog' will be affected by the first 3 rules, so you should replace the <em>changed</em> version to 'wolf' and 'cat'. So for dog => cat:</p> <pre><code>$patterns[] = "/\bdug\b/"; $replacements[] = "cat"; </code></pre> <p>Note: Because of the way preg_replace works with arrays, it's much better to not use indexes in the $patterns and $replacements arrays, since these can be misleading. Use the [] operator in pairs like I did above, so you always know what goes with what.</p> <p>Part 2:</p> <p>Aha. I see. You need to make the replacement exlusive.</p> <p>You could use a regex that matches both the first cases, which are the problematic ones. Then you can use an interesting weird feature of preg_replace: When you add the <code>e</code> modifier, the replace string is instead evaluated as PHP code. Combining this with capturing groups, it will allow you to decide whether to output a <code>u</code> or an <code>i</code> according to what you matched.</p> <pre><code>$patterns[] = "/(?&lt;!\b|[aeiou])([aeiou])(?![aeiou])/e"; $replacements[] = '("$1" == "e" || "$1" == "u")? "i":"u"'; </code></pre> <p>*Note the /e and the () around the vowel matching class.</p>
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    1. POPHP preg_replace multiple rules
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    1. COThanks dude, that works like charm. :) But please see my edited post above.
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    2. COOhh and another thing, you need to make sure you also use lookbehind in your `/ea/` because you said *not at the beginning of a word*.
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    3. COYou are amazing! Thank you so much
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