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    <p><strong>I. A good XSLT 1.0 solution</strong> (brief, efficient and understandable):</p> <pre><code>&lt;xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt; &lt;xsl:output method="text"/&gt; &lt;xsl:template match="/*"&gt; &lt;xsl:for-each select="group"&gt; &lt;xsl:sort select="sum(val)" data-type="number" order="descending"/&gt; &lt;xsl:if test="position()=1"&gt; &lt;xsl:value-of select="sum(val)"/&gt; &lt;/xsl:if&gt; &lt;/xsl:for-each&gt; &lt;/xsl:template&gt; &lt;/xsl:stylesheet&gt; </code></pre> <p><strong>when this transformation is applied on the following XML document</strong>:</p> <pre><code>&lt;t&gt; &lt;group&gt; &lt;val&gt;1&lt;/val&gt; &lt;val&gt;3&lt;/val&gt; &lt;val&gt;1&lt;/val&gt; &lt;/group&gt; &lt;group&gt; &lt;val&gt;3&lt;/val&gt; &lt;val&gt;2&lt;/val&gt; &lt;val&gt;2&lt;/val&gt; &lt;/group&gt; &lt;/t&gt; </code></pre> <p><strong>the wanted, correct result is produced</strong>:</p> <pre><code>7 </code></pre> <p><strong>To get the desired variable definition</strong>, simply put the <code>&lt;xsl:for-each&gt;</code> instruvtion from the above code in the body of the variable.</p> <p><strong>II. An even better XSLT 2.0 (and actually XPath 2.0 one-liner) solution</strong>:</p> <pre><code>&lt;xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt; &lt;xsl:output method="text"/&gt; &lt;xsl:template match="/*"&gt; &lt;xsl:sequence select="max(group/sum(val))"/&gt; &lt;/xsl:template&gt; &lt;/xsl:stylesheet&gt; </code></pre> <p><strong>when this transformation is applied on the same XML document, the same correct answer is produced</strong>:</p> <pre><code>7 </code></pre> <p><strong>And the wanted variable definition is simply</strong>:</p> <pre><code> &lt;xsl:variable name="vHighestSum" select="max(group/sum(val))"/&gt; </code></pre> <p><strong>Finally</strong>, the same Xpath expression can be used in XQuery to define the required variable:</p> <pre><code>let $vHighestSum := max(/*/group/sum(val)) </code></pre>
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    1. COThanks for the very complete answer. The Xpath one-liner worked great, however I found out I can't use this more elegant syntax because (if I understood correctly) .NET does not currently support this. So I used your XSLT 1.0 solution, which works fine as well. Thanks a lot!
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      1. USBram De Moor
 

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