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POCombining <xsl:param> and <xsl:include>
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Id
3381750
data
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3388007
AnswerCount
3
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CommentCount
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CreationDate
2010-08-01T10:58:34.693
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2010-08-02T13:03:26.760
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2010-08-01T22:55:28.933
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text
Body
<p>I'm trying to make a website more dinamically with splitting it in parts. I had a XML file for the first page that now has been converted to 4 files: index.xml, menu.xml, sidebar.xml and footer.xml.</p> <p>(Updated)</p> <p>I include correctly the XML's on the index.xsl file. Now I need to include the .xls that they will use. Actually I've it all in the same file and works fine, so XML include are solved.</p> <pre><code><?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:param name="menu" select="document('../menu.xml')"/> <xsl:param name="sidebar" select="document('../sidebar.xml')"/> <xsl:param name="footer" select="document('../footer.xml')"/> <xsl:template match="/">  <html lang="es"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <title><xsl:value-of select="page/title" /></title> <link rel="stylesheet" type="text/css" href="css/main.css" /> <script type="text/javascript" src="js/custom.js"></script> </head> <body> <div class="content"> <div class="header"> <div id="tabs" class="menu"> <ul> <xsl:for-each select="$menu/menu/category"> <li><a><xsl:attribute name="href"><xsl:value-of select="link" /></xsl:attribute><xsl:value-of select="name"/></a></li> </xsl:for-each> </ul> </div> </div> <div class="body">  <div class="body_izqda"> <xsl:for-each select="page/news/contents/entry"> <h2><xsl:value-of select="title" /></h2> <p><xsl:value-of select="text" /></p> </xsl:for-each> </div>  <div class="body_dcha"> <ul> <xsl:for-each select="$sidebar/sidebar/results/category"> <li> <a><xsl:attribute name="href"><xsl:value-of select="link" /></xsl:attribute><xsl:value-of select="name" /></a> </li> </xsl:for-each> </ul> </div>   <div class="clear"> </div> </div> <div class="footer"> <ul> <xsl:for-each select="$footer/footer/entry"> <li><a><xsl:attribute name="href"><xsl:value-of select="link" /></xsl:attribute><xsl:value-of select="title" /></a></li> </xsl:for-each> </ul> </div> </div> </body> </html>  </xsl:template> </xsl:stylesheet> </code></pre> <p>By the way, I want to split that XLST parts with XLS files. I tried with the <code><xsl:include></code> but I can't get it working with the param $menu.</p> <p>I've marqued with <em>Split</em> and <em>End Split</em> where I need to split the document</p> <p>I already tried to solve with the first reply by @svick, but splitting it with the marks I've done the XSLTPRocessor class for PHP gives me:</p> <blockquote> <p>Warning: XSLTProcessor::importStylesheet() [xsltprocessor.importstylesheet]: element import only allowed as child of stylesheet</p> </blockquote> <p>So, something is wrong with splitting in the way I'm doing and then including it. </p> <p>How can I solve it?</p> <p>Thanks in advance!</p> <p><strong>NOTE1</strong> head.xsl:</p> <pre><code><?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="/"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <title><xsl:value-of select="page/title" /></title> <link rel="stylesheet" type="text/css" href="css/reset-min.css" /> <link rel="stylesheet" type="text/css" href="css/main.css" /> <link rel="stylesheet" type="text/css" href="css/jquery-ui.css" /> </head> </xsl:template> </xsl:stylesheet> </code></pre>
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<xml><xslt><xhtml>
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Combining <xsl:param> and <xsl:include>
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1. COCan you clarify that? How exactly do you want to split it?
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2. CO@svick Hello. I have a XSL that outputs the website from <html> to </html>. I want to split <head /> a <div id="sidebar" /> and <div id="footer" />. The contents of this, will be a on a separated XLS for each one. I don't know if this is more clarify. Sorry, English is not my main language. If you need more explanation, tell me. Thanks in advance!
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