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PO
 

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    <p>Your function is expecting a pointer to the structure. This arguement can be an individual instance of that structure or it could be an element in the array of the give structure. Like</p> <pre><code>struct myStruct { int a, b; long cL, dL; char e; } struc1, struc2, record[20]; </code></pre> <p>and function's prototype will be</p> <pre><code>function( struct myStruct *ptr); </code></pre> <p>Now you can pass the structure to function:</p> <pre><code>function( &amp;struct1 ); // or function( &amp;record[ index] ); </code></pre> <p>Now your confusion arises because of the misconception that syntax <code>array[i]</code> can also be treated as a pointer like we can do with the name of the <code>array</code>. </p> <p><code>record</code> - name of the array- gives the address of the first member of the array, (pointers also point to memory addresses) hence it can be be passed to the function. But <code>record[index]</code>, it is different. <br/></p> <p>Actually, when we write <code>record[ index]</code> it gives us the value placed there which is not a pointer. Hence your function which is accepting a pointer, does not accept it.</p> <p>To make it acceptable to the function, you will have to pass the address of the elements of the array i.e</p> <pre><code>function( &amp;record[ index ] ); </code></pre> <p>Here <code>&amp;</code> operator gives the address of the elements of the array.</p> <p>Alternatively, you can also use:</p> <pre><code>function( record + index ); </code></pre> <p>Here, as we know <code>record</code> is the address of the first element, and when we add <code>index</code> in it, it gives the address of the respective element using pointer arithmetic.</p> <p>Hope it was helpful.</p>
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    1. POI don't understand one dimensional array handling with function passing
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    1. USAndrew-Dufresne
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    1. COreally appreciated ur answer. Thanks for the quick response
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    2. CO@anonymous: Pleasure is all mine.
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    3. COsuppose record is a struture with element char abc[10]; inside it now when i do record[i] -> abc it will give address of abc or value inside the string abc
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