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    <p>Are you trying to get the position of mouse pointer <code>relative</code> to element ( or ) simply the mouse pointer location<br /><br /> Try this Demo : <a href="http://jsfiddle.net/AMsK9/" rel="noreferrer"><strong>http://jsfiddle.net/AMsK9/</strong></a></p> <hr> <h2>Edit :</h2> <p>1) <code>event.pageX</code>, <code>event.pageY</code> gives you the mouse position relative document !</p> <p><strong>Ref</strong> : <a href="http://api.jquery.com/event.pageX/" rel="noreferrer">http://api.jquery.com/event.pageX/</a><br> <a href="http://api.jquery.com/event.pageY/" rel="noreferrer">http://api.jquery.com/event.pageY/</a></p> <p>2) <code>offset()</code> : It gives the offset position of an element</p> <p><strong>Ref</strong> : <a href="http://api.jquery.com/offset/" rel="noreferrer">http://api.jquery.com/offset/</a></p> <p>3) <code>position()</code> : It gives you the relative Position of an element i.e.,</p> <p>consider an element is embedded inside another element </p> <p><strong>example</strong> : </p> <pre><code>&lt;div id="imParent"&gt; &lt;div id="imchild" /&gt; &lt;/div&gt; </code></pre> <p><strong>Ref</strong> : <a href="http://api.jquery.com/position/" rel="noreferrer">http://api.jquery.com/position/</a></p> <p><strong><em>HTML</em></strong></p> <pre><code>&lt;body&gt; &lt;div id="A" style="left:100px;"&gt; Default &lt;br /&gt; mouse&lt;br/&gt;position &lt;/div&gt; &lt;div id="B" style="left:300px;"&gt; offset() &lt;br /&gt; mouse&lt;br/&gt;position &lt;/div&gt; &lt;div id="C" style="left:500px;"&gt; position() &lt;br /&gt; mouse&lt;br/&gt;position &lt;/div&gt; &lt;/body&gt; </code></pre> <p><strong><em>JavaScript</em></strong></p> <pre><code>$(document).ready(function (e) { $('#A').click(function (e) { //Default mouse Position alert(e.pageX + ' , ' + e.pageY); }); $('#B').click(function (e) { //Offset mouse Position var posX = $(this).offset().left, posY = $(this).offset().top; alert((e.pageX - posX) + ' , ' + (e.pageY - posY)); }); $('#C').click(function (e) { //Relative ( to its parent) mouse position var posX = $(this).position().left, posY = $(this).position().top; alert((e.pageX - posX) + ' , ' + (e.pageY - posY)); }); }); </code></pre>
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    1. CO+1 for the examples...one note though I'd also add the code here, if your link dies this question becomes useless in the future, I'd put the code for each and a brief description here :)
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      1. USNick Craver
    2. COThere is a simpler way to do the case of `'#B'`: `e.offsetX` and `e.offsetY`. I guess you'd like to edit it. I already updated the fiddle [here](http://jsfiddle.net/AMsK9/101/). I found this solution thanks to the post, so thanks.
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