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    <p>Your parser code will have to remember which sort of layer it's currently in at the time of the START_TAG event for a tile tag.</p> <p>One way to do this is to create a field <code>String currentLayer;</code> and somewhere in your code have code segments resembling</p> <pre><code>if (xrp.getEventType() == XmlResourceParser.END_TAG) { String s = xrp.getName(); if (s.equals("layer")) { currentLayer = null; // or something ... } } </code></pre> <p>and</p> <pre><code>if (xrp.getEventType() == XmlResourceParser.START_TAG) { String s = xrp.getName(); if (s.equals("layer")) { currentLayer = xrp.getAttributeValue(null, "name", 0); } } </code></pre> <p>Then in your code dealing with the tile tag, you'll use that field to decide which action to take with something resembling</p> <pre><code>if (xrp.getEventType() == XmlResourceParser.START_TAG) { String s = xrp.getName(); if (s.equals("tile")) { int a = xrp.getAttributeIntValue(null, "gid", 0); if ("layer1".equals(currentLayer) { // process layer1 tile. } else if ("layer2".equals(currentLayer) { // process layer2 tile. } else { // handle occurrence of tile outside layer. } } } </code></pre> <p>This is not necessarily the best approach, especially if it leads to huge nested if-else constructs, but this might get you started.</p> <p>A better approach might be to have a field for a delegate that handles tiles, set it to an appropriate "tile-processor" object (which you'll have to define as a separate class) during the start event handling for the layer tag and use it in the handling of the tile tag. But that's harder to put in code snippets.</p>
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    1. POhow to differentiate xml tags that belong to layer1 and those that belong layer2 if they use the same tag name?
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    1. USDon Roby
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    1. POhow to differentiate xml tags that belong to layer1 and those that belong layer2 if they use the same tag name?
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    1. COdpb and donroby, both answer were very useful i have it working now thanks !
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      1. USfreeaks
    2. CO@freeaks - Good to hear! If you accept one of the answers or even post and accept your own with how you actually solved the problem, it will help all.
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      1. USDon Roby
 

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