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POF#+.Net, calculation error using the System.Math.Floor function
 

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    <p>here's a function I wrote to print every digit of a float number in F#:</p> <pre><code>let rec TestFloor (fnum:float) = let floor = System.Math.Floor(fnum) printfn "fnum:%f floor:%f" fnum floor if floor &gt; 0.0 then TestFloor((fnum - floor) * 10.0) </code></pre> <p>Anyway the result is strange, for example:</p> <pre><code>&gt; TestFloor 1.23;; fnum:1.230000 floor:1.000000 fnum:2.300000 floor:2.000000 **fnum:3.000000 floor:2.000000** fnum:10.000000 floor:9.000000 fnum:10.000000 floor:9.000000 fnum:10.000000 floor:9.000000 fnum:10.000000 floor:9.000000 fnum:10.000000 floor:9.000000 fnum:10.000000 floor:9.000000 fnum:10.000000 floor:9.000000 fnum:10.000000 floor:9.000000 fnum:9.999998 floor:9.000000 fnum:9.999982 floor:9.000000 fnum:9.999822 floor:9.000000 ... </code></pre> <p>At the fourth line the floor of 3.0 turned out to be 2.0 which is strange. The following computations are all going wrong. I'm wondering what's happening there?</p> <p>Thanks!</p> <hr> <p><strong>Edit 2</strong></p> <p>@ sepp2k</p> <p>This is the result after using %.30f:</p> <pre><code>&gt; TestFloor 1.23;; fnum:1.230000000000000000000000000000 floor:1.000000000000000000000000000000 fnum:2.300000000000000000000000000000 floor:2.000000000000000000000000000000 **fnum:3.000000000000000000000000000000 floor:2.000000000000000000000000000000** fnum:9.999999999999980000000000000000 floor:9.000000000000000000000000000000 fnum:9.999999999999820000000000000000 floor:9.000000000000000000000000000000 fnum:9.999999999998220000000000000000 floor:9.000000000000000000000000000000 fnum:9.999999999982240000000000000000 floor:9.000000000000000000000000000000 fnum:9.999999999822360000000000000000 floor:9.000000000000000000000000000000 </code></pre> <p>As you can see at the fourth line <code>fnum</code> is <code>3.00...</code> and the <code>floor</code> value is <code>2.00..</code></p> <hr> <p><strong>Edit 3 - Solved</strong></p> <p>Thank you all, now I understand what the problem is about.</p>
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