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POVirtualization in Super Class Constructor
 

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    <p>I was of the opinion that virtualization doesnt work in the super class constructor as per the design of OOP. For example, consider the following C# code. </p> <pre><code>using System; namespace Problem { public class BaseClass { public BaseClass() { Console.WriteLine("Hello, World!"); this.PrintRandom(); } public virtual void PrintRandom() { Console.WriteLine("0"); } } public class Descendent : BaseClass { private Random randomValue; public Descendent() { Console.WriteLine("Bonjour, Monde!"); randomValue = new Random(); } public override void PrintRandom() { Console.WriteLine(randomValue.NextDouble().ToString()); } public static void Main() { Descendent obj = new Descendent(); obj.PrintRandom(); Console.ReadLine(); } } } </code></pre> <p>This code breaks because when the object of Descendent is made, it calls the base class constructor and we have a virtual method call in Base Class constructor which in turn calls the Derived class's method and hence, it crashes since randomValue is not intialized by that time.</p> <p>A similar code works in C++ because the call to PrintRandom is not routed to the derived class since IMO, the order in C++ is something like:</p> <p><br>1. call for base class constructor <br>2. Update V - Table for this class <br>3. call the constructor code</p> <p>My Question is that firstly whether I am right that as per OOP principles, virtualization shouldn't/doesn't work in the super class constructor and secondly if I am right, then why the behavior is different in all .NET languages ( I have tested it with C#, VB.NET and MC++)</p>
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