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    <p><code>b*</code> means "match zero or more occurences of <code>b</code>".</p> <p><code>.</code> means "match any character except newline".</p> <p><code>[EE|EJU]</code> means "match an <code>E</code>, a <code>|</code>, a <code>J</code> or a <code>U</code>". </p> <p><code>.*</code> means "match any character except newline zero or more times".</p> <p><code>D</code> means "match a <code>D</code>".</p> <p>So the regex is doing what you asked it to do. </p> <p>From the examples you provided in your question, I'm guessing that the actual rules should be:</p> <ol> <li>String starts with <code>KD-R35</code>.</li> <li>Then any number of alphanumeric characters may follow, as long as</li> <li>there is an <code>E</code>, a <code>J</code> or a <code>U</code> among them, and</li> <li>the string ends in <code>D</code>.</li> </ol> <p>These rules, as a regex, read:</p> <pre><code>^ # start of string KD-R35 # literal text ( # start of capturing group \w* # any number of alphanumeric characters [EJU] # at least one of E, J, or U \w* # any number of alphanumeric characters D # a D ) # end of capturing group $ # end of string </code></pre> <p>or, in JavaScript:</p> <pre><code>match = subject.match(/^KD-R35(\w*[EJU]\w*D)$/i); if (match != null) { // successful match mytext = match[1] // capturing group 1 } else { // Match attempt failed } </code></pre> <p>I'm assuming that upper/lowercase don't matter.</p> <p>EDIT: Erm, your new edit changes the rules. It seems that any string is allowed as long as it starts with <code>KD-R35</code> and ends in <code>D</code>. In this case, the regex would simply be <code>/^KD-R35(\w*D)$/i</code>.</p>
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    1. USTim Pietzcker
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    1. COlook at my edited question
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    2. COit seems like a same problem..always show KD-35H2UND,H2UND
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    3. COI don't understand. `match[0]` contains the entire string ("KD-R35H2UND"), `match[1]` contains the variable part ("H2UND"). It is not possible to match only `H2UND` if it's preceded by `KD-R35` because JavaScript doesn't support lookbehind assertions.
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