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    <p>It depends if the function is a <em>function template</em> or not. </p> <p>In <strong>C++ Templates -- the complete guides</strong>, Jusuttis provides a different definition of that given in the C++ standard, but with equivalent consequences:</p> <p>We define the signature of a function as the the following information:</p> <ol> <li>The <em>unqualified name</em> of the function</li> <li>The <em>class</em> or <em>namespace</em> scope of that name, and if the name has internal linkage, the translation unit in which the name is declared</li> <li>The <code>const</code>, <code>volatile</code>, or <code>const volatile</code> qualification of the function</li> <li>The <em>types</em> of the function parameters</li> <li><strong>its return <em>type</em>, if the function is generated from a function template</strong></li> <li>The <em>template parameters</em> and the <em>template arguments</em>, if the function is generated from a function template</li> </ol> <p>As <strong>litb</strong> suggested, it's worth to clarify why the return type is part of the signature of a template function. </p> <blockquote> <p>Functions can coexist in a program if they have distinct signatures.</p> </blockquote> <p>. That said, if the return type is a template parameter:</p> <pre><code>template &lt;typename T&gt; T foo(int a) {return T();} </code></pre> <p>it's possibile to instantiate two function which differ only in the return type:</p> <pre><code>foo&lt;int&gt;(0); foo&lt;char&gt;(0); </code></pre> <p>Not only: as rightly reported by <strong>litb</strong>, it is also possible to overload two template functions, which differ only in the return type, even if the return type is not a dependent name. Here's his example:</p> <pre><code>template&lt;class T&gt; int foo(T) {} template&lt;class T&gt; bool foo(T) {} // at the instantiation point it is necessary to specify the cast // in order not to face ambiguous overload ((int(*)(char))foo&lt;char&gt;)('a'); </code></pre>
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    1. POIs the return type part of the function signature?
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    1. USNicola Bonelli
    1. USNicola Bonelli
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    1. COIt says in a footnote "This definition is different from that given by the C++ Standard, but its consequences are equivalent". Thus that is the definition of some book, but not of C++.
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      1. USJohannes Schaub - litb
    2. COIf you read this post carefully you can find the footnote in the second sentence :-)
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      1. USNicola Bonelli
    3. COThe point they wanted to make is that function templates can coexist like this in the same scope: template<class T> int foo(T); template<class T> bool foo(T); int main() { ((int(*)(char))foo<char>)('a'); }
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      1. USJohannes Schaub - litb
 

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