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PO
primarykey
Id
2870499
data
AcceptedAnswerId
0
AnswerCount
0
ClosedDate
CommentCount
0
CommunityOwnedDate
CreationDate
2010-05-20T01:28:47.030
FavoriteCount
0
LastActivityDate
2010-05-20T01:38:04.813
LastEditDate
2017-05-23T12:07:07.397
LastEditorUserId
-1
OwnerUserId
276101
ParentId
2870393
PostTypeId
2
Score
6
ViewCount
0
LastEditorDisplayName
text
Body
<p>Your <code>useDelimiter()</code> and <code>next()</code> combo is faulty. <code>useDelimiter("")</code> will return 1-length substring on <code>next()</code>, because an empty string does in fact sit between every two characters.</p> <p>That is, because <code>"\r\n".equals("\r" + "" + "\n")</code> so <code>"\r\n"</code> are in fact two tokens, <code>"\r"</code> and <code>"\n"</code>, delimited by <code>""</code>.</p> <p>To get the <code>Matcher</code>-behavior, you need <code>findWithinHorizon</code>, which ignores delimiters.</p> <pre><code> Pattern newLinePattern = Pattern.compile("(\\r\\n?|\\n)", Pattern.MULTILINE); String sourceString = "\r\n\n\r\r\n\n"; Scanner scan = new Scanner(sourceString); int count = 0; while (scan.findWithinHorizon(newLinePattern, 0) != null) { count++; } System.out.println("found "+count+" newlines"); // finds 5 newlines </code></pre> <h3>API links</h3> <ul> <li><a href="http://java.sun.com/javase/6/docs/api/java/util/Scanner.html#findWithinHorizon%28java.util.regex.Pattern,%20int%29" rel="nofollow noreferrer"><code>findWithinHorizon(Pattern pattern, int horizon)</code></a> <blockquote> <p>Attempts to find the next occurrence of the specified pattern [...] ignoring delimiters [...] If no such pattern is detected then the <code>null</code> is returned [...] If <code>horizon</code> is 0, then [...] this method continues to search through the input looking for the specified pattern without bound.</p> </blockquote></li> </ul> <h3>Related questions</h3> <ul> <li><a href="https://stackoverflow.com/questions/2597841/scanner-method-to-get-a-char">Scanner method to get a char</a> <ul> <li><code>useDelimiter("")</code> will tokenize into 1-length substrings</li> </ul></li> </ul>
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1. POJava Scanner newline parsing with regex (Bug?)
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