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    <p>Unfortunately, there is no good, portable way to do this that I know of. If you attempt to parse /etc/group, as others are suggesting, you will miss users who have that group as their primary group and anyone who has been added to that group via a mechanism other than UNIX flat files (i.e. LDAP, NIS, pam-pgsql, etc.).</p> <p>If I absolutely had to do this myself, I'd probably do it in reverse: use <code>id</code> to get the groups of every user on the system (which will pull all sources visible to NSS), and use Perl or something similar to maintain a hash table for each group discovered noting the membership of that user.</p> <p>Edit: Of course, this leaves you with a similar problem: how to get a list of every user on the system. Since my location uses only flat files and LDAP, I can just get a list from both locations, but that may or may not be true for your environment.</p> <p>Edit 2: Someone in passing reminded me that <code>getent passwd</code> will return a list of all users on the system including ones from LDAP/NIS/etc., <em>but</em> <code>getent group</code> still will still miss users that are members only via the default group entry, so that inspired me to write this quick hack.</p> <pre><code> #!/usr/bin/perl -T # # Lists members of all groups, or optionally just the group # specified on the command line # # Copyright © 2010-2013 by Zed Pobre (zed@debian.org or zed@resonant.org) # # Permission to use, copy, modify, and/or distribute this software for any # purpose with or without fee is hereby granted, provided that the above # copyright notice and this permission notice appear in all copies. # use strict; use warnings; $ENV{"PATH"} = "/usr/bin:/bin"; my $wantedgroup = shift; my %groupmembers; my $usertext = `getent passwd`; my @users = $usertext =~ /^([a-zA-Z0-9_-]+):/gm; foreach my $userid (@users) { my $usergrouptext = `id -Gn $userid`; my @grouplist = split(' ',$usergrouptext); foreach my $group (@grouplist) { $groupmembers{$group}->{$userid} = 1; } } if($wantedgroup) { print_group_members($wantedgroup); } else { foreach my $group (sort keys %groupmembers) { print "Group ",$group," has the following members:\n"; print_group_members($group); print "\n"; } } sub print_group_members { my ($group) = @_; return unless $group; foreach my $member (sort keys %{$groupmembers{$group}}) { print $member,"\n"; } } </code></pre>
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    1. POHow to list all users in a Linux group?
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    1. POHow to list all users in a Linux group?
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    1. COThanks to all who answered. I was looking for a portable way to do it. Your information that there's not an easy and portable way was helpful. You also detailed the most on the circumstances which helped me understand the problem more deeply, I appreciate that and I chose your answer as the accepted one.
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    2. COWould it be possible for you to donate your script to the Linux foundation? It is 2012 and there are still no easy way to get the members of a group. That is the thing that frustrate me about Linux.
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    3. COI added an ISC-like license for you, which should be compatible with just about any group. Feel free to submit it anywhere you think it will be accepted.
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